<h2>Answer:</h2>
The distance will be 1800 m
<h2>Explanation</h2>As in question
Time = 15 min
Time = 15 x 60 sec = 900 sec
Speed = 2 m/s
We know that
So, the answer is 1800 m
Upon its return voyage from a space mission, the spacecraft has a velocity of 25000 km/h at point A, which is 7130 km from the c
enter of the earth. Determine the velocity of the spacecraft when it reaches point B, which is 6625 km from the center of the earth. The trajectory between these two points is outside the effect of the earth’s atmosphere. The radius of the earth is 6371 km, and g = 9.825 m/s2 on the surface of the earth.
1 answer:
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Answer:
Explanation:
Given
mass of laptop m=2 kg
The velocity of car u=8 m/s
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The coefficient of kinetic friction is
As the car is moving, so the coefficient of kinetic friction comes into play
deceleration offered by friction
Using the equation of motion
insert the values