<h3>
Answer: </h3><h3>
speed of train A = 44 mph</h3>
=============================================
Work Shown:
x = speed of train A
y = speed of train B
"train A travels 4/5 the speed of train B" (I'm assuming "train one" is supposed to read "train B"). So this means x = (4/5)y
distance = rate*time
d = x*7
d = (4/5)y*7 = (28/5)y represents the distance train A travels
d = y*7 = 7y represents the distance train B travels
summing those distances will give us 693
(28/5)y + 7y = 693
5*( (28/5)y + 7y ) = 5*693
28y + 35y = 3465
63y = 3465
y = 3465/63
y = 55
Train B's speed is 55 mph
4/5 of that is (4/5)y = (4/5)*55 = 4*11 = 44 mph
Train A's speed is 44 mph
Using: loga b = log b / log a
1) a=x+3, b=4 → y1=log4 (x+3) → y1= log (x+3) / log 4
2) a=2+x, b=2 →y2=log2 (2+x) → y2=log (2+x) / log 2
Answer:
y1=log (x+3) / log 4, y2= log (2+x) / log 2
Answer: 15 centimeters
Step-by-step explanation: You cut the rectangle into two triangles following the diagonal. You add 12 squared (144) and 9 squared (81) together. You get 225. You get the square root of 225 which is 15 and that is your answer. Basic solving for the hypotenuse.
We've hit on a case where a measure of center does not provide all the information spread or variability there is in month-to-month precipitation. based on how busy each month has been in the past, lets managers plan
