The volume of a sphere is: 4/3 (pi) (radius cubed.) You would use that formula to solve for the volume.
Answer:
C. 70
Step-by-step explanation:
In the expansion of (a + b)^n, the k-th term is ...
nCk·a^(n-k)b^k . . . . . k = 0 to n; nCk = n!/(k!(n-k)!)
Here, we have n=8, k=4, so the term of interest is ...
8C4·x^4y^4 = (8·7·6·5)/(4·3·2·1)x^4y^4 = 70x^4y^4
The coefficient of the term is 70.
Answer:
x+ 3/2y= 15
Step-by-step explanation:
8x+12y=120
To put the equation into standard form, the leading coefficient has to be 1. So, divide the whole equation by 8.
x+ 3/2y= 15
The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula:

Were

is the area in square kilometers

is one of the sides of the square
We know for our problem that the side lengths of the field are 0.9 kilometers, so

. Lets replace that value in our formula to find

:

Now, to find the population density of the filed, we are going to use the population density formula:

where

is the population density in <span>in burrows per square kilometer
</span>

is the number of burrows

is the are of the field
We know that

and

, so lets replace those values in our formula:


We can conclude that the <span>density of prairie dog burrows is approximately
2444 burrws per square kilometer.</span>
As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1
As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.
Given, a△b=a^2-b/b-a^2
now 4△3 = (4^2-3) / (3-4^2)
4△3 = (16-3) / (3-16)
4△3 = 13 / -13
4△3 = -1
Hence, as the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1.
- Mathematical operation: An operator in mathematics is often a mapping or function that transforms components of one space into elements of another.
To learn more about mathematical operation, click on the link given below:
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