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qwelly [4]
3 years ago
14

Adjoa’s gross salary for last month was Ghc4,687.24. If Ghc421.78 was deducted from Adjoa’s salary pay, how much take-home pay d

id Adjoa earn this past month?
Mathematics
1 answer:
Zina [86]3 years ago
3 0

The amount  that Adjoa earn as his take-home pay this past month is Ghc4,265.46.

Using this formula

Net pay=Gross pay-Deduction

Where:

Gross pay=Ghc4,687.24

Deduction= Ghc421.78

Let plug in the formula

Net pay=Ghc4,687.24- Ghc421.78

Net pay= Ghc4,265.46

Inconclusion the amount  that Adjoa earn as his take-home pay this past month is Ghc4,265.46.

Learn more here:

brainly.com/question/25292658

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What is the volume of a sphere with a radius of 24 units ?
GarryVolchara [31]
The volume of a sphere is: 4/3 (pi) (radius cubed.) You would use that formula to solve for the volume. 
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4 years ago
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What is the coefficient of x^4y^4 in the expansion (x+y)^8?
Ivanshal [37]

Answer:

  C.  70

Step-by-step explanation:

In the expansion of (a + b)^n, the k-th term is ...

  nCk·a^(n-k)b^k . . . . . k = 0 to n; nCk = n!/(k!(n-k)!)

Here, we have n=8, k=4, so the term of interest is ...

  8C4·x^4y^4 = (8·7·6·5)/(4·3·2·1)x^4y^4 = 70x^4y^4

The coefficient of the term is 70.

3 0
3 years ago
Pls help me! (more info in photo)
goldfiish [28.3K]

Answer:

x+ 3/2y= 15

Step-by-step explanation:

8x+12y=120

To put the equation into standard form, the leading coefficient has to be 1. So, divide the whole equation by 8.

x+ 3/2y= 15

8 0
3 years ago
Mr. Sánchez owns a square field. The side lengths are 0.9 kilometers. There are 1,980 prairie dog burrows in the fields. What is
Simora [160]
The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula: A=s^2
Were 
A is the area in square kilometers 
s is one of the sides of the square
We know for our problem that  the side lengths of the field are 0.9 kilometers, so s=0.9. Lets replace that value in our formula to find A:
A=(0.9)^2
A=0.81 

Now, to find the population density of the filed, we are going to use the population density formula: P_{d}= \frac{I}{A}
where
P_{d} is the population density in <span>in burrows per square kilometer
</span>I is the number of burrows 
A is the are of the field
We know that I=1980 and A=0.81, so lets replace those values in our formula:
P_{d}= \frac{1980}{0.81}
P_{d}=2444.4

We can conclude that the <span>density of prairie dog burrows is approximately 2444 burrws per square kilometer.</span>
5 0
3 years ago
A new operation is defined by a△b=a^2-b/b-a^2. 4△3.
dmitriy555 [2]

As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1

As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.

Given, a△b=a^2-b/b-a^2

now 4△3 = (4^2-3) / (3-4^2)  

4△3 = (16-3) / (3-16)        

4△3 = 13 / -13  

4△3 = -1

Hence, as the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1.

  • Mathematical operation: An operator in mathematics is often a mapping or function that transforms components of one space into elements of another.

To learn more about mathematical operation, click on the link given below:

brainly.com/question/8959976

#SPJ1        

8 0
1 year ago
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