we know that
For a polynomial, if
x=a is a zero of the function, then
(x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.
So
In this problem
If the cubic polynomial function has zeroes at 2, 3, and 5
then
the factors are
Part a) Can any of the roots have multiplicity?
The answer is No
If a cubic polynomial function has three different zeroes
then
the multiplicity of each factor is one
For instance, the cubic polynomial function has the zeroes
each occurring once.
Part b) How can you find a function that has these roots?
To find the cubic polynomial function multiply the factors and equate to zero
so
therefore
the answer Part b) is
the cubic polynomial function is equal to
Interest is 100*(2/100)
$2
Answer:
x(x - 2)
Step-by-step explanation:
x² - 2x ← factor out x from each term
= x(x - 2)
Answer:
Nominal
Step-by-step explanation:
Data can be divided into 2 types:
- Qualitative Data
- Quantitative Data
Qualitative data represent some attribute or characteristic and cannot be measured or calculated. This type of data uses Nominal or Ordinal level of measurement.
Quantitative data is the data which can be measure or calculated. This type of data is expressed in Ratio or Interval scale.
Different genres of music represent an attribute, hence the data is Qualitative. Qualitative data which can put into some order is at Ordinal scale of measurement, while if the data simply represent the name or attributes it would be at Nominal Level.
Different genres of music cannot be put into some order and are just names, hence the measurement scale would be Nominal.
Complete question :
a ladder 5 meters long is leaning against a wall. the base of the ladder is sliding away from the wall at a rate of 1 meter per second. how fast is the top of the ladder sliding down the wall at the instant when the base is 4 meters from the wall?
Answer:
-4/3 m/s
Step-by-step explanation:
Using Pythagoras :
a² = x² + c²
5² = x² + y² - - - (1)
The horizontal distance x with respect to time t = 1m/sec
dx/dt = 1m/sec
To obtain the vertical height 'y' with respect to time t when x = 4
5² = x² + y²
Wen x = 4
5² = 4² + y²
25 = 16 + y²
y =√(25 - 16)
y = 3
Differentiate (1) with respect to t
x² + y² = 25 - ---- - (1)
2x * dx /dt + 2y dy/dt = 0
dx/dt = 1
x = 4.
y = 3
2(4)(1) + 2(3) * dy/dt = 0
8 + 6dy/dt = 0
6 dy/dt = - 8
dy/dt = - 8/6
dy/dt = - 4/3
