Question

How does the mean absolute deviation (MAD) of the data in set 1 compare to the mean absolute deviation of the data in set 2? Set 1: 12, 8, 10, 50 Set 2: 13, 9, 8

Answer 1

Answer:

The Mean Absolute Deviation of Set 1 is 13 more than the mean absolute deviation of Set 2.

Step-by-step explanation:

Set 1: 12, 8, 10, 50

Set 2: 13, 9, 8

Step 1:We determine the mean for each set

Mean of Set 1: $=\dfrac{12+8+10+50}{4} =\dfrac{80}{4}=20$

Mean of Set 2:$=\dfrac{13+9+8}{3} =\dfrac{30}{3}=10$

Step 2: We determine the mean absolute deviation (MAD) of the data in each set.

M.A.D of Set 1: $=\dfrac{|12-20|+|8-20|+|10-20|+|50-20|}{4} =\dfrac{8+12+10+30}{4}=\dfrac{60}{4}=15$

Mean of Set 2:$=\dfrac{|13-10|+|9-10|+|8-10|}{3} =\dfrac{3+1+2}{3}=\dfrac{6}{3}=2$

The Mean Absolute Deviation of Set 1 is 13 more than the mean absolute deviation of Set 2.

Answer 2

Answer:

With math

Step-by-step explanation:

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