Plz refer to the attachment
If it helps you plzz brainliest me...
You can solve this problem through factoring.
First, you have the equation,

Then, you can factor the numerator.

You can cancel out the x-6 in both the numerator and the denominator because they would equal to just 1.
You are left with 
The function is removable noncontinuous at x=6 because if you plug in 6 in x-6, your denominator would be undefined.
The answer would be y=(x+4)^2-37
Answer:
a and b.
Step-by-step explanation:
I’ll explain by giving an example.
Let’s say that: a=3;b=4;c=5; => they all are consecutive -> their sum is 12.
=> if we use a) n=3 => 3*n+3=3*3+3=12 => correct.
b) n+(n+1)+(n+2)= 3+4+5=12=> correct.
c)n+2n+3n=3+6+9=18=>incorrect.
d)3n=3*3=9=>incorrect.