Answer:
it's 28 because
2:8
4:16
6:24
7:28
so there are 28 tablespoons in 7 cups to make Grandmas cookie pie
(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ
quester [9]
Answer:
<h2>5</h2>
Step-by-step explanation:
Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.
On expanding the left hand side of the expression we have;
= (8x² −15x)−(x² −27x)
Open the paranthesis
= 8x² −15x−x²+27x
collect the like terms
= 8x²−x²+27x −15x
= 7x²+12x
Comparing the resulting expression with ax²+bx
7x²+12x = ax²+bx
7x² = ax²
a = 7
Also;
12x = bx
b =12
The value of b - a = 12 - 7
b -a = 5
Hence the value of b-a is equivalent to 5
First, we need to know the smallest two digit prime number. It can't start with one, since one is not prime, so it must start with two (or be in the twenties.) 20 is divisible by 2, 4, 5, and 10, 21 is divisible by 7 and 3, 22 is divisible by 2 and 11, so the smallest prime number is 23.
Now we need the largest two-digit prime number. It cannot start with nine or eight, since both are composite, so it must start with seven (be in the seventies.) 79 is the largest integer in the seventies and also happens to be prime, so there's our largest two digit prime number.
now we just need to add them for the sum:
23+79=102
hope I helped, and let me know if you have any questions :D
Answer:
![x^{2} - 5x - 24](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-%205x%20-%2024)
Step-by-step explanation:
( x + 3 )( x - 8 ) =
- 8x + 3x - 24 =
- 5x -24
Answer:
Step-by-step explanation:
Null hypothesis should be: The average woman's leg hair grows an eighth of an inch per month: u = eighth of an inch
Alternative hypothesis: The average woman's leg hair growth is not an eighth of an inch per month after treatment: u ≠ eighth of an inch
This test after carrying out its treatment will be able to determine if the drug was effective or not