Answer:
ax² + bx + c
Step-by-step explanation:
The form of a quadratic equation that is easy to use when finding the maximum or minimum value of the function is ax² + bx + c.
Suppose a quadratic function:
f(x) = 2x² - 8x + 9
Use ( -b/2a , f(-b/2a) ).
-b/2a
a = 2
b = -8
-(-8)/2(2)
8/4
= 2
f(2) = 2(2)² - 8(2) + 9
f(2) = 2(4) - 8(2) + 9
f(2) = 8 - 16 + 9
f(2) = 1
The minimum value of this quadratic function is (2, 1).
It represents a minimum value because a > 0.
The answer is -1 7/8 in lowest terms.
<span>n = 11<span>.
Explanation:
Let m be the number of boxes Mark sells and a be the number of boxes Ann sells.
Since Mark sells 10 less than n, m = n-10. Since Ann sells 2 less than n, a = n-2.
Together, they sold n-10+n-2=2n-12 boxes.
We know that they sold less than n boxes, so our inequality would be
2n-12<n.
To solve this, subtract n from both sides:
2n-12-n<n-n; n-12<0.
Add 12 to both sides:
n-12+12<0+12; n<12.
This means there were less than 12 boxes. The next number down is 11; this woks because Mark sold 10 less than n; 11-10=1. Mark sold at least 1 box.
If n=10, however, 10-10=0; this doesn't work, because Mark did sell at least 1 box. </span></span>
Answer:
D
Step-by-step explanation:
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