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Setler [38]
2 years ago
11

Determine the number of moles in 3.13 × 10²³ formula units of MgCl₂.

Chemistry
1 answer:
love history [14]2 years ago
3 0

Answer:

<h2>0.52 moles </h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.13 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{3.13}{6.02}  \\  = 0.519933

We have the final answer as

<h3>0.52 moles</h3>

Hope this helps you

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See solution.

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Hello there!

In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:

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Thus, we solve for the molar mass of the metal to obtain:

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4.00gO_2*\frac{1molO_2}{32.00gO_2}=0.125molO_2

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Answer:

The final volume of air after compression: V₂ = 4477.63 L = 158.12 cf

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Initial Temperature = 70°F

⇒ T₁ = (70°F − 32) × 5/9 + 273.15 = 294.26 K

Initial volume of the gas: V₁ = 1200 cf = 1200 × 28.317  = 33980.4 L    (∵ 1 cf ≈ 28.317  L)

Final gauge pressure of the gas = 90 psi

Final absolute pressure of the gas: P₂ = gauge pressure + atmospheric pressure = 90 psi + 12.20 psi = 102.2 psi

Final Temperature: T₂ = 125°F

⇒ T₂ = (125°F − 32) × 5/9 + 273.15 = 324.82 K

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I hope u find it helpful

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