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prohojiy [21]
2 years ago
5

Hi, im really confused can someone help

Chemistry
1 answer:
GenaCL600 [577]2 years ago
3 0
Lol I don’t know anything about this sorry
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What are alternative periodic tables
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Tabulations of chemical elements differing in their organization from the traditional seen periodic system
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3 years ago
The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
Kipish [7]

Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)

According to stoichiometry:

1 mole of C_3H_8 requires 5 moles of oxygen

0.45 moles of C_3H_8 require= \frac{5}{1}\times 0.45=2.25 moles of oxygen

Mass of O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g

72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

7 0
3 years ago
H4X - pKa1 =1.5
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8 0
2 years ago
If 30.5 g of 15% potassium nitrate solution are reacted to excess magnesium chloride how many grams of potassium chloride will b
Nata [24]
Here the step by step and answer

4 0
2 years ago
Calculate the number of moles of carbon dioxide formed when 40.0 moles of oxygen is consumed in the burning of propane. Note the
joja [24]
The first step is to balance the equation:


<span>C3H8 + 5O2 ---> 3CO2 + 4H2O


Check the balance


element          left side        right side

C                    3                  3  
H                    8                  4*2 = 8
O                    5*2=10        3*2 + 4 = 10


Then you have the molar ratios:


3 mol C3H8 : 5 mol O2 : 3 mol CO2 : 4 mol H2O


Now you have 40 moles of O2 so you make the proportion:

40.0 mol O2 * [3 mol CO2 / 5 mol O2] = 24.0 mol CO2.


Answer: option D. 24.0 mol CO2
</span>
7 0
3 years ago
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