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Irina18 [472]
3 years ago
14

Without using technology determine if the function is even or odd and describe its end behavior: () = 3 − 2 + 4 + 2

Mathematics
1 answer:
zhenek [66]3 years ago
6 0

Answer:

7 maybe this is the answer please correct me if I'm wrong

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A random sample of 101 lightning flashes in a certain region resulted in a sample average radar echo duration of 0.81 sec and a
Masteriza [31]

Answer:

The 99% (two-sided) confidence interval for the true average echo duration μ is between 0 sec and 1.99 sec.

Step-by-step explanation:

We have the sample standard deviation, so we use the student t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 101 - 1 = 100

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.6259

The margin of error is:

M = T*s = 2.6259*0.45 = 1.18

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.81 - 1.18. Answer in seconds cannot be negative, so we use 0 sec.

The upper end of the interval is the sample mean added to M. So it is 0.81 + 1.18 = 1.99 sec

The 99% (two-sided) confidence interval for the true average echo duration μ is between 0 sec and 1.99 sec.

6 0
3 years ago
PLEASE HELP ME NEED ASAP!!!!
rosijanka [135]

Answer:

It should be (0, 24)

Step-by-step explanation:

I hope this helped.

4 0
3 years ago
Read 2 more answers
An object, which is at the origin at time t=0, has initial velocity V0= (-14.0i - 7.0j)m/s and constant acceleration a=(6.0i + 3
sesenic [268]
I am pretty sure the first thing we should do is to <span>integrate acceleration into velocity
And we will have: </span>a(t) = \ \textless \ 6,3\ \textgreater \v(t) = \ \textless \ (6t+C),(3t+C)\ \textgreater \ ; where    -- v(0) = \ \textless \ -14,-7\ \textgreater \
Then calculate v :&#10;v(t) = \ \textless \ (6t-14),(3t-7)\ \textgreater \
As you can see, velocity is zero and none of the objects is moving. It happens when <span> t=7/3 which means we can calculate this in the way we did (integrating) :
</span>p(t) = \ \textless \  (3t^2-14t+C) , ((3/2)t^2-7t+C) \ \textgreater \ &#10;
The product is <span>p(0) = 0 that makes us to reduce vector function to</span>p(t) = \ \textless \  (3t^2-14t) , ((3/2)t^2-7t) \ \textgreater \   where t = 7/3p(7/3) = \ \textless \  -49/3 , -49/6 \ \textgreater \<span>

</span>
7 0
4 years ago
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Solve for a missing factor,
Eva8 [605]

Answer:

1. 32

2. 170

3. 29

Step-by-step explanation:

1. is just 10 divided by 320, which gives you 32

2. is 10 times 17 which is 170

3. you need 29 tens to get 290.

6 0
3 years ago
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How does a digit in the ten thousand place compare to a digit in the thousands place
Artemon [7]
A digit in its 10 thousandths place is 10 times more than a digit in its thousandths place.
4 0
3 years ago
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