Answer:
The 99% (two-sided) confidence interval for the true average echo duration μ is between 0 sec and 1.99 sec.
Step-by-step explanation:
We have the sample standard deviation, so we use the student t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 101 - 1 = 100
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.6259
The margin of error is:
M = T*s = 2.6259*0.45 = 1.18
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 0.81 - 1.18. Answer in seconds cannot be negative, so we use 0 sec.
The upper end of the interval is the sample mean added to M. So it is 0.81 + 1.18 = 1.99 sec
The 99% (two-sided) confidence interval for the true average echo duration μ is between 0 sec and 1.99 sec.
Answer:
It should be (0, 24)
Step-by-step explanation:
I hope this helped.
I am pretty sure the first thing we should do is to <span>integrate acceleration into velocity
And we will have: </span>


Then calculate v :

As you can see, velocity is zero and none of the objects is moving. It happens when <span> t=7/3 which means we can calculate this in the way we did (integrating) :
</span>

The product is <span>p(0) = 0 that makes us to reduce vector function to</span>


<span>
</span>
Answer:
1. 32
2. 170
3. 29
Step-by-step explanation:
1. is just 10 divided by 320, which gives you 32
2. is 10 times 17 which is 170
3. you need 29 tens to get 290.
A digit in its 10 thousandths place is 10 times more than a digit in its thousandths place.