Answer:
0.00125 moles H₃X
Solution and Explanation:
In this question we are required to calculate the number of moles of triprotic acid neutralized in the titration.
Volume of NaOH used = final burette reading - initial burette reading
= 39.18 ml - 3.19 ml
= 35.99 ml or 0.03599 L
Step 1: Moles of NaOH used
Number of moles = Molarity × Volume
Molarity of NaOH = 0.1041 M
Moles of NaOH = 0.1041 M × 0.03599 L
= 0.00375 mole
Step 2: Balanced equation for the reaction between triprotic acid and NaOH
The balanced equation is;
H₃X(aq) + 3NaOH(aq) → Na₃X(aq) + 3H₂O(l)
Step 3: Moles of the triprotic acid (H₃X used
From the balanced equation;
1 mole of the triprotic acid reacts with 3 moles of NaOH
Therefore; the mole ratio of H₃X to NaOH is 1 : 3.
Therefore;
Moles of Triprotic acid = 0.00375 mole ÷ 3
= 0.00125 moles
Hence, moles of triprotic acid neutralized during the titration is 0.00125 moles.
Answer:
hydrogen ions
Explanation:
Acids are substances that when dissolved in water release hydrogen ions, H+(aq). Bases are substances that react with and neutralise acids, producing water. When dissolved, bases release hydroxide ions, OH-(aq) into solution. Water is the product of an acid and base reacting.
Answer:
See below ~
Explanation:
Sea water has a <u>high amount of salt present</u> in it. The density of salt is <u>higher than that of water</u>. It <u>dissolves in water</u>, thereby increasing its density. Hence, this is why sea water has a higher density than tap water.
Answer:
89.1 N
Explanation:
W = m gm = 55.0 x 1.62 = 89.1 N
Answer:
B. is coupled to the production of ATP
Explanation:
The magnesium in chlorophyll acts as an activator of enzymes associated with energy metabolism, especially respiratory enzymes and others that act on phosphorylated substrates such as ATP.
