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DerKrebs [107]
3 years ago
12

If you were a given a beaker containing a clear solution (with no solid solute at the bottom), what simple test would you do to

determine if it is saturated or unsaturated solution?​
Chemistry
1 answer:
raketka [301]3 years ago
6 0

Answer:

put a filter to see if there is any stagering solution

Explanation:

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What happen when iron reacts with copper sulphate​
Darina [25.2K]

Fe(s) + CuSO4(aq) -> Cu(s) + FeSO4(aq) is the answer if you get it in advance...

3 0
4 years ago
Without atmospheric pressure humans could not do what?
MariettaO [177]

Answer:

Breathe. Breathing is the number one thing every human does, and their bodies need it. Think about going in a pool in 6 feet. You realize that its kinda hard to breathe and it feels like something is holding your chest down really hard. Water pressure and air pressure can affect the breathing habits of a human and can also cause suffocation to the lungs.

Explanation:

please give brainlyest

7 0
3 years ago
50 POINTSSSSS PLZ HELPPPPPP NEED TO SHOW WORK!!!!
VashaNatasha [74]
(4 mol H2O) x (112 kJ / 3 mol H2O) = 149 kJ 

<span>(14.5 g HCl) / (36.4611 g HCl/mol) x (112 kJ / 3 mol HCl) = 14.9 kJ </span>

<span>(475 kJ) / (181 kJ / 2 mol HgO) x (216.5894 g HgO/mol) = 1137 g HgO </span>

<span>(179 kJ) / (181 kJ / 1 mol O2) x (31.99886 g O2/mol) = 31.6 g O2 </span>

<span>(145 kJ) / (112 kJ / 3 mol Cl2) x (70.9064 g Cl2/mol) = 275 g Cl2 </span>

<span>(14.5 g S2Cl2) / (135.0360 g S2Cl2/mol) x (112 kJ / 1 mol S2Cl2) = 12.0 kJ </span>

<span>CaCO3 + 2 NH3 → CaCN2 + 3 H2O; ∆H = –90.0 kJ </span>
<span>(798 kJ) / (90.0 kJ / 2 mol HN3) x (17.03056 g NH3/mol) = 302 g NH3 </span>

<span>(19.7 g H2O) / (18.01532 g H2O/mol) x (90.0 kJ / 3 mol H2O) = 32.8 kJ</span>
5 0
3 years ago
A container initially holds 1.24mol of hydrogen gas and has a volume of 27.8L. Hydrogen gas was added to the container, and the
Fantom [35]

Answer:

After increasing the volume, we have 1.81 moles of hydrogen gas in the container

Explanation:

Step 1: Data given

Number of moles hydrogen gas (H2) = 1.24 moles

Volume of hydrogen gas (H2° = 27.8 L

The final volume is increas to 40.6 L

Step 2: Calculate the new number of moles

V1/n1 = V2/n2

⇒with V1 = the initial volume = 27.8 L

⇒with n1 = the initial number of moles H2 = 1.24 moles

⇒with V2 = the final volume = 40.6 L

⇒with n2 = the new number of moles = TO BE DETERMINED

27.8L / 1.24 moles = 40.6 L / n2

n2 = 40.6 / (27.8/1.24)

n2= 1.81 moles

After increasing the volume, we have 1.81 moles of hydrogen gas in the container

3 0
3 years ago
A chemist obtains a 0.300 M solution of HCI and adds 10.0 mL of the HCI to CaCO3 how many moles of HCI did she add?
Salsk061 [2.6K]

Answer:

Number of moles = 0.003 mol

Explanation:

Given data:

Molarity of HCl = 0.300 M

Volume = 10.0 mL (0.01 L)

Number of moles of HCl added = ?

Solution:

Formula:

Molarity = number of moles / volume in litter

Number of moles = Molarity ×  volume in litter

Number of moles =  0.300 mol/L × 0.01 L

Number of moles = 0.003 mol

4 0
3 years ago
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