Answer:

Step-by-step explanation:
Solve for p:
i = prt
i = prt is equivalent to prt = i:
prt = i
Divide both sides by rt:



Answer:
-x/x^2-1
Step-by-step explanation:
-x^2+x/x^3-x^2-x+1
x(-x+1)/(x+1)(x-1)(x-1)
-x/x^2-1
Answer:
Step-by-step explanation:
The total they want to raise is $2,400 if that is what you're asking?
Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)

=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)