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ElenaW [278]
3 years ago
11

uniform mementum mas is 90g is pivoted at 40cm mark if the metra rula ia in equilibrium with an mark unknown mass m place at the

10cm mark and mass of 73g place at 70cm .ditermine the value of m when mass of an object is always at it center of gravity​

Physics
1 answer:
Cerrena [4.2K]3 years ago
6 0

Answer:

Unknown mass, m = 14 \textrm{ g}

Explanation:

From the figure below,

OE is a meter scale with markings in centimeter.

A is the position of unknown mass m, B is the position of 90 g mass, C is the fulcrum, D is the position of mass 73 g.

Length AC = 40 cm, BC = 10 cm, CD = 20 cm

For equilibrium of the meter scale,

Sum of anti-clockwise moments = Sum of clockwise moments

F_{A}\times AC+F_{B}\times BC=F_{D}\times CD\\m\times 40+90\times10=73\times20\\40m+900=1460\\40m=1460-900\\40m=560\\m=\frac{560}{40}=14\textrm{ g}

Therefore,unknown mass is 14 g.

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6 0
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A 0.050 kg metal bolt is heated to an unknown initial temperature. It is then dropped into calorimeter containing 0.15 kg of wat
Pachacha [2.7K]

The initial temperature of the metal bolt is 80.8 °C

We'll begin by calculating the heat absorbed by the water.

  • Mass of water (M) = 0.15 Kg
  • Initial temperature (T₁) = 21 °C
  • Final temperature (T₂) = 25 °C
  • Change in temperature (ΔT)  = T₂ – T₁ = 25 – 21 = 4 °C
  • Specific heat capacity of water (C) = 4184 J/KgºC
  • Heat absorbed (Q) =?

Q = MCΔT

Q = 0.15 × 4184 × 4

Q = 2510.4 J

Finally, we shall determine the initial temperature of the metal bolt.

  • Heat absorbed by water = 2510.4 J
  • Heat released by metal (Q) = –2510.4 J
  • Mass of metal (M) = 0.050 Kg
  • Final temperature (T₂) = 25 °C
  • Specific heat capacity of metal (C) = 899 J/Kg°C
  • Initial temperature (T₁) =?

Q = MC(T₂ – T₁)

–2510.4 = 0.050 × 899 (25 – T₁)

–2510.4 = 44.95 (25 – T₁)

Clear bracket

–2510.4 = 1123.75 – 44.95T₁

Collect like terms

–2510.4 – 1123.75 = –44.95T₁

–3634.15 = –44.95T₁

Divide both side by –44.95

T₁ = –3634.15 / –44.95

T₁ = 80.8 °C

Thus, the initial temperature of the metal is 80.8 °C.

Learn more about heat tranfer:

brainly.com/question/26034272

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2 years ago
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