Explanation:
It is given that,
Length of the copper wire, l = 4.4 m
Diameter of copper wire, d = 1.3 mm = 0.0013 m
Radius of copper wire, r = 0.00065 m
The resistivity of the copper wire, 
We need to find the resistance of the copper wire. It is given by :
R =0.055 ohms
So, the resistance of the copper wire is 0.055 ohms. Hence, this is the required solution.
Answer:
P V = N R T ideal gas equation
P2 / P1 = T2 / T1 where the other variables are constant
P2 = (T2 / T1) * P1 = (313 / 293) * 40 psi = 42.7 psi
The first one, as the mass is higher so it accelerates more
Answer:
a) a = 4.9 m / s², N = 16.97 N and b) F = 9.8 N
Explanation:
a) For this exercise we will use Newton's second law, we write a reference system with the x axis parallel to the plane, see attached, in this system the only force we have to break down is weight, let's use trigonometry
sin 30 = Wx / W
cos 30 = Wy / W
Wx = W sin30
Wy = W cos 30
Let's write the equations on each axis
X axis
Wx = ma
Y Axis
N- Wy = 0
N = Wy = mg cos 30
N = 2.0 9.8 cos 30
N = 16.97 N
We calculate the acceleration
a = Wx / m
a = mg sin 30 / m
a = g sin 30
a =9.8 sin 30
a = 4.9 m / s²
b) For the block to move with constant speed, the acceleration must be zero, so the force applied must be equal to the weight component
F -Wx = 0
F = Wx
F = m g sin 30
F = 2.0 9.8 sin 30
F = 9.8 N
The speed increases, because as the angle increases (the wing slants up more steeply), the air has to go farther to get over the wing.
