Answer:
3.83×10⁻¹⁹ J
Explanation:
The energy of a photon can be found using the formula: E=hc/λ
- h is Planck's Constant which is approximately 6.63×10⁻³⁴
- c is the speed of light which we'll round to 3.00×10⁸
- λ is the wavelength of the photon. You typed 5200 but that's not even within the visible light spectrum's wavelength range, so I'm going to assume you meant 520 nm; or 5.20×10⁻⁷ m.
Plugging all that info in should give approximately 3.83×10⁻¹⁹ Joules of energy.
(You could get slight variations depending on what you chose to round up or down or not at all.)
Answer:
M=28.88 gm/mol
Explanation:
Given that
T= 95 K
P= 1.6 atm
V= 4.87 L
m = 28.6 g
R=0.08206L atm .mol .K
We know that gas equation for ideal gas
P V = n R T
P=Pressure , V=Volume ,n=Moles,T= Temperature ,R=gas constant
Now by putting the values
P V = n R T
1.6 x 4.87 = n x 0.08206 x 95
n=0.99 moles
We know that number of moles given as

M=Molar mass


M=28.88 gm/mol
First, volcanic eruptions produce major quantities of carbon dioxide (CO2), a gas known to contribute to the greenhouse effect. ... The small ash particles decrease the amount of sunlight reaching the surface of the earth and lower average global temperatures.
It sounds like a special relativity question but I need more info for a total answer. But remember it's length in the lab frame is
L•sqrt(1-(v/c)^2) where L is the rest length, v is its velocity magnitude and c is the speed of light. Sqrt is the square root (I'm on a phone so I can't see the math equation editor)
I think you want to determine the exit speed?
You have to determine how much velocity was decreased by calculating it from the kinetic energy.
KE = (1/2)mv²
1.4 x 10^5 = (1/2)*(1100)v²
v² = 254.55
v =15.95 m/s
So the velocity reduces by 15.95 m/s. Subtracting this to the initial velocity: 22 - 15.95 = 6.05 m/s.
So, the final speed was 6.05 m/s.
I hope I was able to help :)