Force = mass * acceleration
F = 15 *8 = 120 Newton
Let's use the mirror equation to solve the problem:
![\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bf%7D%3D%20%5Cfrac%7B1%7D%7Bd_o%7D%2B%20%5Cfrac%7B1%7D%7Bd_i%7D%20%20%20)
where f is the focal length of the mirror,
![d_o](https://tex.z-dn.net/?f=d_o)
the distance of the object from the mirror, and
![d_i](https://tex.z-dn.net/?f=d_i)
the distance of the image from the mirror.
For a concave mirror, for the sign convention f is considered to be positive. So we can solve the equation for
![d_i](https://tex.z-dn.net/?f=d_i)
by using the numbers given in the text of the problem:
![\frac{1}{12 cm}= \frac{1}{5 cm}+ \frac{1}{d_i}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B12%20cm%7D%3D%20%5Cfrac%7B1%7D%7B5%20cm%7D%2B%20%5Cfrac%7B1%7D%7Bd_i%7D%20%20%20)
![\frac{1}{d_i}= -\frac{7}{60 cm}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bd_i%7D%3D%20-%5Cfrac%7B7%7D%7B60%20cm%7D%20%20)
![d_i = -8.6 cm](https://tex.z-dn.net/?f=d_i%20%3D%20-8.6%20cm)
Where the negative sign means that the image is virtual, so it is located behind the mirror, at 8.6 cm from the center of the mirror.
If a coin is dropped at a relatively low altitude, it's acceleration remains constant. However, if the coin is dropped at a very high altitude, air resistance will have a significant effect. The initial acceleration of the coin will be the greatest. As it falls down, air resistance will counteract the weight of the coin. So, the acceleration will decrease. Although the acceleration decreases, the coin still accelerates, that is why it falls faster. When the air resistance fully counters the weight of the coin, the acceleration will become zero and the coin will fall at a constant speed (terminal velocity). So, the answer should be, The acceleration decreases until it reaches 0. The closest answer is.
a. The acceleration decreases.
Fahrenheit because the boiling point of water is 100 degrees Celsius which is 212 Fahrenheit which is very hot, and that would be about 200 Kelvin so therefore the answer is that the temperature was recorded in Fahrenheit not Kelvin or Celsius
Explanation:
both are areas of land that drain to particular water bodies such as lakes