PLSSS HELP IF YOU TURLY KNOW THISS

Mathematics

2 answers:

e-lub [12.9K]2 years ago

6 0

Answer:

$8^{2}$

Step-by-step explanation:

You add the exponents if ur multiplying them with the same base, which is 8.

3 + (-2) + 1

3 - 2 + 1

So the answer is $8^{2}$

Nikolay [14]2 years ago

4 0

8²

(8^3)(8^-2)(8^1)

=512(8^-2)(8^1)

=512(1/64)(8^1)

=8(8^1)

=(8)(8)

=64

√64=8

(8•8 so 8²)

You might be interested in

Y^3-27=9y^2-27y how to factor

Kryger [21]

Hello! And thank you for your question!

First we are going to redo the equation:

y^3−3y^2(3)+3(y)×3^2−3^3=0

Then we are going to use Cube of Difference:

0 = (y - 3)^3

That take cube root of both sides:

0 = y - 3

Finally add 3 to both sides:

3 = y

Final Answer:

y = 3

4 0

3 years ago

Consider the function below. (If an answer does not exist, enter DNE.) g(x) = 190 + 8x3 + x4 (a) Find the interval of increase.

galben [10]

Answer:

The interval of increase of g(x) is $(-6,+\infty)$ .

Step-by-step explanation:

The interval of increase occurs when first derivative of given function brings positive values. Let be $g(x) = 190 + 8 \cdot x^{3} + x^{4}$ , the first derivative of the function is:

$g'(x) = 24 \cdot x ^{2} + 4\cdot x^{3}$

$g'(x) = 4 \cdot x^{2}\cdot (6+x)$

The following condition must be met to define the interval of increase:

$4\cdot x^{2} \cdot (x+6) > 0$

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

$x + 6 > 0$