<span>the empirical formula is C3H8O2
You need to determine the relative number of moles of hydrogen and carbon. So you first calculate the molar mass of CO2 and H20
Atomic weight of carbon = 12.0107
Atomic weight of hydrogen = 1.00794
Atomic weight of oxygen = 15.999
Molar mass CO2 = 12.0107 + 2 * 15.999 = 44.0087
Molar mass H2O = 2 * 1.00794 + 15.999 = 18.01488
Now calculate the number of moles of CO2 and H2O you have
Moles CO2 = 2.086 g / 44.0087 g/mole = 0.0474 mole
Moles H2O = 1.134 g / 18.01488 g/mole = 0.062948 mole
Calculate the number of moles of carbon and hydrogen you have. Since there's 1 carbon atom per CO2 molecule, the number of moles of carbon is the same as the number of moles of CO2. But since there's 2 hydrogen atoms per molecule of H2O, The number of moles of hydrogen is double the number of moles of H2O
Moles Carbon = 0.0474
Moles Hydrogen = 0.062948 * 2 = 0.125896
Now we need to determine how much oxygen is in the compound. Just take the mass of the compound and subtract the mass of carbon and hydrogen. What's left will be the mass of oxygen. Then divide that mass by the atomic weight of oxygen to get the number of moles of oxygen we have.
1.200 - 0.0474 * 12.0107 - 0.125896 * 1.00794 = 0.503797
Moles oxygen = 0.503797 / 15.999 = 0.031489
So now we have a ratio of carbon:hydrogen:oxygen of
0.0474 : 0.125896 : 0.031489
We need to find a ratio of small integers that's close to that ratio. Start by dividing everything by 0.031489 (selected because it's the smallest value) getting
1.505288 : 3.998095 : 1
The 1 for oxygen and the 3.998095 for hydrogen look close enough. But the 1.505288 for carbon doesn't work. But it looks like if we double all the numbers, we'll get something close to an integer for everything. So do so.
3.010575 : 7.996189 : 2
Now this looks good. Rounding everything to an integer gives us
3 : 8 : 2
So the empirical formula is C3H8O2</span>
Answer:
32.7 grams of Zn will remained in the crucible after cooling.
Explanation:
..[1]
..[2]
Adding [1] + 2 × [2] we get:
..[3]
Moles of ZnS in crucible = 0.50 mol
According to reaction [3]. 2 moles of ZnS gives 2 moles of Zn.
Then 0.50 moles of ZnS will give:
of Zn.
Mass of 0.50 moles of Zn =
= 0.50 mol × 65.4 g/mol =32.7 g
32.7 grams of Zn will remained in the crucible after cooling.
ANSWER
THE PENTANES
EXPLANATION
he word for5 in Greek is PENT like the 5 sided and 5 angled building in Wachington the PENTagon.
SO C5H12 IS PENTAND BECAUSE IT HAS NO DOUBLE BONDAS IT IS AN ALKANE
SO SO C5H12 IS PENT-ANE PENTANE AND THERE ARE MULTIPLE FORMS OF IT
In a chemical bonding the electrons that are in the outer most orbital are the one's involved in bonding. The aim of bonding is that each of the atoms must have an octet of electons ( but there are exception which do not follow this rule ) in their valence orbital in order to become stable.Atoms can either loses, gain or share electrons in order to reach this desired state. In a case where they share, they might share all their valence electrons either with the same or different atoms or a certain number of their electron which will end up with them having eight electrons in their valence orbital. Once the atoms have bonded, the remaining electrons that are not shared between the atoms are called the unshared elctron pair and the electrons that are shared and involved in forming bonds are called the shared electron pair. the unshared electron pair can be shared with another atom that has lost it's electrons, this pair is then called a lone pair.
