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3 years ago

How should the enthalpy of an intermediate step be manipulated when used to produce an overall chemical equation?

2 answers:

8 0

The enthalpy of an intermediate step when used to produce an overall chemical equation should be manipulated in this way:
Multiply the enthalpy by –1 if the chemical equation is reversed.
If the forward reaction requires energy, the reverse will produce energy.

AVprozaik [17]3 years ago

8 0

Ans: Multiply the enthalpy by –1 if the chemical equation is reversed.

Enthalpy is a thermodynamic state function which represents the heat content of a system. For chemical reactions, enthalpy can be used to predict if the reaction is endothermic or exothermic.

If the enthalpy of the reactants is greater than products, the reaction is exothermic. If the reactants have a lower enthalpy than products, then the reaction is exothermic.

For a multistep reaction, the enthalpy of the intermediate step should be multiplied by -1 if the chemical reaction needs to be reversed in order to get the overall reaction.

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If a farmer wants to increase the health of his crops, he could apply a nitrogen-based fertilizer. why is nitrogen important to

Finger [1]

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3 years ago

IS THIS A BALANCED EQUATION MgCl2 + Na2O -- > MgO + 2 NaCl

Dmitriy789 [7]

Yes, this is balanced. Each part of the substance (like Mg) has the same number on both sides.

Hope this helps you:)

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3 years ago

KClO3 (s) KCl (s) + 02 (g) How do you balance this equation

Vitek1552 [10]

Answer:

2KCl(s) + 6O3O2

Explanation:

I think it's correct

7 0

3 years ago

Lead(II) oxide from an ore can be reduced to elemental lead by heating in a furnace with carbon. Calculate the expected yield of

Lelu [443]

Answer:

53kg is the expected yield of lead

Explanation:

Firstly, in order to solve this question, we need to write the equation of reaction correctly. This is as follows:

PbO(s) + C(s) ---> Pb(l) + CO(g)

We proceed from here. We should get the limiting reactant but this can only be obtained by getting the number of moles of each reactant present.

The formula to use across all boards is that the number of moles is the mass of each of the reactant divided by the molar mass of each of the reactant.

For PBO, mass is 57kg = 57000g

Molar mass of PBO = 223.20g/mol

The number of moles is thus 57,000/223.2 = 255.37 moles

For carbon, mass is also 57kg = 57000g

Molar mass is 12g/mol

Number of moles of carbon = 57000/12 = 4750 moles

From the number of moles, we can see that the number of moles of Carbon is greater than that of PbO. This means that PbO is the limiting reagent.

Hence we use it to calculate percentage yield.

The number of moles of lead formed is the same of number of moles of lead oxide = 255.37 since we have mole ratio of 1 to 1

The molar mass of lead is 207.20g/mol

The mass of lead formed is = moles of lead formed * molar mass of lead = 207.20 * 255.37 = 52,912g which is approximately 53kg

Hence the expected yield is 53kg

6 0

3 years ago

HELP ASAP

Bezzdna [24]

A. I think sorry if it’s wrong

5 0

3 years ago