Answer:
The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Step-by-step explanation:
Let the random variable <em>X</em> denote the water depths.
As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.
The probability density function of <em>X</em> is:

Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:

![=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B5.00%7D%5Cint%5Climits%5E%7B5.00%7D_%7B2.25%7D%20%7B1%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D0.20%5Ctimes%20%5Bx%5D%5E%7B5.00%7D_%7B2.25%7D%20%5C%5C%5C%5C%3D0.20%5Ctimes%20%285.00-2.25%29%5C%5C%5C%5C%3D0.55)
Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Answer:
Square
Step-by-step explanation:
Answer:
Step-by-step explanation:
First, turn the word problem into an equation:
n(a number) was divided by 2

followed by this quotient beying multiplied by 4
*4
the product was added to 9
*4+9
the total sum was 25
*4+9 = 25
use PEMDAS to solve the equation
subtract 9 on both sides
*4 = 16
cancel the 2 and the 4 using factorization
n*2 = 16
divide 2 on both sides
n = 8
Answer:
False.
Step-by-step explanation:
Point (1, -1) is located in Quadrant 4, while point (-1, 1) is in Quadrant 2.
I hope this helps...have a great day! ❤