1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marin [14]
2 years ago
5

How many examples are there for oscillatory motion (i) Motion of football players (ii) String of a guitar (iii) Motion of a chil

d on a swing (iv) Rotating fan (f) Surface of drums (vi) Moving of bicycles on road (vii) Rolling of a ball on ground
is Apurva account ban ??​
Physics
1 answer:
andrew11 [14]2 years ago
7 0

Answer:

yesssssss mere followers mein dekho Mrs Queen I'd hai uska follow her ☺

I'm a baby so I don't know the answer

You might be interested in
A merry-go-round spins freely when Diego moves quickly to the center along a radius of the merry-go-round. As he does this, it i
kaheart [24]

Answer:

The moment of inertia of the system decreases and the angular speed increases.

Explanation:

This very concept might not seem to be interesting at first, but in combination with the law of the conservation of angular momentum, it can be used to describe many fascinating physical phenomena and predict motion in a wide range of situations.

In other words, the moment of inertia for an object describes its resistance to angular acceleration, accounting for the distribution of mass around its axis of rotation.

Therefore, in the course of this action, it is said that the moment of inertia of the system decreases and the angular speed increases.

5 0
3 years ago
A 1.1-kg object is suspended from a vertical spring whose spring constant is 120 N/m. (a) Find the amount by which the spring is
andriy [413]

Answer:

e = 0.0898m

v = 2.07m/s

Explanation:

a) According to Hooke's law

F = ke

e is the extension

k is the spring constant

Since F = mg

mg = ke

e = mg/k

Substitute the given value

e = 1.1(9.8)/120

e = 10.78/120

e = 0.0898m

Hence it is stretched by 0.0898m from its unstrained length

2) Total Energy = PE+KE+Elastic potential

Total Energy = mgh +1/2mv²+1/2ke²

Substitute the given value

5.0= 1.1(9.8)(0.2)+1/2(1.1)v²+1/2(120)(0.0898)²

Solve for v

5.0 = 2.156+0.55v²+0.48338

5.0-2.156-0.48338= 0.55v²

2.36 =0.55v²

v² = 2.36/0.55

v² = 4.29

v ,= √4.29

v = 2.07m/s

Hence the required velocity is 9.28m/s

4 0
3 years ago
A 1.50-kg iron horseshoe initially at 550°C is dropped into a bucket containing 25.0 kg of water at 20.0°C. What is the final te
Ber [7]

Answer:

Te =  23.4 °C

Explanation:

Given:-

- The mass of iron horseshoe, m = 1.50 kg

- The initial temperature of horseshoe, Ti_h = 550°C

- The specific heat capacity of iron, ci = 448 J/kgC

- The mass of water, M = 25 kg

- The initial temperature of water, Ti_w = 20°C

- The specific heat capacity of water, cw = 4186 J/kgC

Find:-

What is the final temperature of the water–horseshoe system?

Solution:-

- The interaction of horseshoe and water at their respective initial temperatures will obey the Zeroth and First Law of thermodynamics. The horseshoe at higher temperature comes in thermal equilibrium with the water at lower temperature. We denote the equilibrium temperature as (Te) and apply the First Law of thermodynamics on the system:

                             m*ci*( Ti_h - Te) = M*cw*( Te - Ti_w )

- Solve for (Te):

                             m*ci*( Ti_h ) + M*cw*( Ti_w ) = Te* (m*ci + M*cw )

                             Te = [ m*ci*( Ti_h ) + M*cw*( Ti_w ) ] / [ m*ci + M*cw ]

- Plug in the values and evaluate (Te):

                             Te = [1.5*448*550 + 25*4186*20 ] / [ 1.5*448 + 25*4186 ]

                             Te = 2462600 / 105322

                             Te =  23.4 °C    

7 0
3 years ago
Read 2 more answers
Every object that has mass attracts every other object with a gravitational force: It has been proven that the size of the
denpristay [2]

Answer:

this is a law because it is a constant fact of nature

Explanation:

7 0
3 years ago
Read 2 more answers
WhAT is the change IN THE entropy of 2.0kg of h2o molecules when transform at a constant pressure of 1 atm from water at 100 deg
Fynjy0 [20]

Answer:

The entropy change is 45.2 kJ/K.

Explanation:

mass of water at 100 C = 2 kg

Latent heat of vaporization, L = 2260 kJ/kg

Heat is

H = m L

H = 2 x 2260 = 4520 kJ

Entropy is given by

S = H/T = 4520/100 = 45.2 kJ/K

3 0
2 years ago
Other questions:
  • you paddle a canoe with the force of 200N. you and the canoe have a combined mass of 97KG . what is the acceleration of the cano
    7·1 answer
  • Which is the correct formula for sulfur dichloride
    8·2 answers
  • What is a resource that is constantly being replenish
    12·1 answer
  • IN a physics lab, a student discovers that the magnitude of the magnetic field at a certain distance from a long wire is 4.0μT.
    10·1 answer
  • Which illustration best demonstrates longitudinal waves?
    5·1 answer
  • Help with these questions please?
    10·1 answer
  • Please round to three sig fig
    8·1 answer
  • What color in the visible spectrum has the longest wavelength?
    10·2 answers
  • A plane is traveling at a velocity of 90 m/s. It accelerates at a constant rate of 1.5 m/s​2 until its velocity reaches 500 m/s.
    9·1 answer
  • What happens to the gravitational force between two objects if:
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!