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lora16 [44]
3 years ago
9

Please answer faast!!!

Physics
1 answer:
Drupady [299]3 years ago
7 0

Answer:

Any medium or material of high refractive density e.g Water which refracts the light rays 1&2 away from their normal

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Given a double slit apparatus with slit distance 2 mm, what is the theoretical maximum number of bright spots that I would see w
katen-ka-za [31]

Answer:

The values is  m_{max} = 8001 \  bright \ spots

Explanation:

From the question we are told that

    The slit distance is  d  =  2 \ mm  =  2*10^{-3} \ m

    The  wavelength is  \lambda =  500 \ nm =  500 *10^{-9} \ m

At the first half of the screen from the central maxima

   The number of bright spot according to the condition for constructive interference is  

          n  =  \frac{d *  sin (\theta )}{\lambda}

For maximum number of spot \theta =  90^o

So  

       n  =  \frac{2*10^{-3} *  sin (90 )}{500 *10^{-9}}

        n  =4000

Now for the both sides plus the central maxima  we have

      m_{max} = 2 * n  + 1

substituting values

       m_{max} = 2 *  4000 + 1

       m_{max} = 8001 \  bright \ spots

   

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