Kinetic Energy is calculated by KE= 1/2mv2
Answer:
Work Done = 67.5 J
Explanation:
First we find the value of spring constant (k) using Hooke's Law. Hooke's is formulated as:
F = kx
where,
F = Force Applied = 450 N
k = Spring Constant = ?
x = Stretched Length = 30 cm = 0.3 m
Therefore,
450 N = k(0.3 m)
k = 450 N/0.3 m
k = 1500 N/m
Now, the formula for the work done in stretching the spring is given as:
W = (1/2)kx²
Where,
W = Work done = ?
k = 1500 N/m
x = 70 cm - 40 cm = 0.3 m
Therefore,
W = (1/2)(1500 N/m)(0.3 m)²
<u>W = 67.5 J</u>
The answer will be b but check it by yourself we are humans
Answer:
2.31J
Explanation:
the energy for a spring system is given by:
where 
is the spring constant: 
and 
is the distance stretched from the equilibrium position.
In the first case 
so the energy to stretch the spring 1.81cm is:
and for the second case, the energy to stretch the spring 5.79cm:
so to answer a) we must find the difference between these energies:
Answer:
787.5 V/m
Explanation:
the formula to find the electric field in the region between the plates is
E = V/d
where
V=the voltage supplied by the battery (potential)
d=distance between the plates.
E=electric field
Given:
V= 6.3 V
d= 1.6cm/2=> 0.016m/2
E= V/d=> 6.3/(0.016/2)
E= 787.5 V/m
Therefore, the electric field in the region between the plates is 787.5 V/m
