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SCORPION-xisa [38]
2 years ago
7

What could you do to increase the volume of the gas in a jar?

Chemistry
2 answers:
Leona [35]2 years ago
5 0

An increase in the number of gas molecules in the same volume container increases pressure.

A decrease in container volume increases gas pressure.

An increase in temperature of a gas in a rigid container increases the pressure.

beks73 [17]2 years ago
4 0

Decrease the pressure

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What does the lysosome do
Ostrovityanka [42]

Answer: They digest excess or worn out organelles, food particles, and engulfed viruses or bacteria.

Explanation:

6 0
3 years ago
Read 2 more answers
Determine whether the following hydroxide ion concentrations ([OH−]) correspond to acidic, basic, or neutral solutions by estima
Rzqust [24]

Answer:

See explanation below

Explanation:

To do this, we will use the following expression to calculate the [H⁺]:

[H⁺] = Kw / [OH⁻]

[H⁺] is the same as [H₃O⁺]. So we have the [OH⁻] so, let's replace every value into the above expression to calculate the hydronium concentration and say if it's acidic, basic or neutral. This can be known because if the [H⁺] > 1x10⁻⁷ M the solution is acidic. If it's [H⁺] < 1x10⁻⁷ M the solution is basic, and if it's [H⁺] = 1x10⁻⁷ M the solution is neutral.

a) [H⁺] = 1x10⁻¹⁴ / 6x10⁻¹² = 1.67x10⁻³ M. Acidic.

b) [H⁺] = 1x10⁻¹⁴ / 9x10⁻⁹ = 1.11x10⁻⁶ M. Acidic.

c) [H⁺] = 1x10⁻¹⁴ / 8x10⁻¹⁰ = 1.25x10⁻⁵ M. Acidic.

d) [H⁺] = 1x10⁻¹⁴ / 7x10⁻¹³ = 0.0143 M. Acidic.

e) [H⁺] = 1x10⁻¹⁴ / 2x10⁻² = 5x10⁻¹³ M. Basic.

f) [H⁺] = 1x10⁻¹⁴ / 9x10⁻⁴ = 1.11x10⁻¹¹ M. Basic.

g) [H⁺] = 1x10⁻¹⁴ / 5x10⁻⁵ = 2x10⁻¹⁰ M. Basic.

h) [H⁺] = 1x10⁻¹⁴ / 1x10⁻⁷ = 1x10⁻⁷ M. Neutral.

Part B.

In this part, we'll use the following expression and replace the given values:

[OH⁻] = Kw / [H⁺]

Replacing the values:

[OH⁻] = 1x10⁻¹⁴ / 5.2x10⁻⁵

[OH⁻] = 1.92x10⁻¹⁰ M

PArt C:

In this case, we will use expression of part A, and replace the given values:

[H⁺] = 1x10⁻¹⁴ / 2.7x10⁻²

[H⁺] = 3.7x10⁻¹³ M

8 0
2 years ago
Based on the information, what is the balanced chemical equation representing the burning of butane?
kompoz [17]

Answer:

OptionA. 2C4H10 + 13O2 —> 8CO2 + 10H20

Explanation:

Butane burns is air (O2) according to the equation:

C4H10 + O2 —> CO2 + H20

Considering the equation, it is evident that it not balanced. Now let us balance the equation as shown below;

There are a total of 4 carbon atoms on the left and 1 carbon atom on the right. It can be balanced by putting 4 in front of CO2 as shown below:

C4H10 + O2 —> 4CO2 + H20

Next, there are 10 hydrogen atoms on the left and 2 hydrogen atoms on the right. Therefore to balance it, put 5 in front of H2O as shown below:

C4H10 + O2 —> 4CO2 + 5H20

Now, there are a total of 13 oxygen atoms on the right and 2 at the left. To balance it, put 13/2 in front of O2

as shown below

C4H10 + 13/2O2 —> 4CO2 + 5H20

Now we multiply through by 2 clear off the fraction and we obtained:

2C4H10 + 13O2 —> 8CO2 + 10H20

6 0
3 years ago
Suppose that a solution is tested for NO2 ion by adding 3M H2SO4 and heating, repeating this process until no further reaction o
Arada [10]

Answer:

The correct equation will be "[Fe(H2O)5]²⁺ + NO → Fe(H2O)5NO]²+ (brown ring) ".

Explanation:

For NO₂, the addition of H₂SO₄ forms HNO₂ comprising NO gas as well as HNO₂, the equation will be:

⇒  NO₂⁻ + 2H⁺ →  HNO2

⇒  HNO₂ + H₂O + H⁺  →  HNO₃ + NO

For NO₃⁻,

NO₃⁻, Fe₂+ oxidized to Fe₃ + then releases NO gas in the existence of H₂SO₄

⇒  3Fe₂⁺ + 4H⁺ + NO₃⁻  →  3Fe₃⁺ + NO + 2H₂O

Brown ring forming establishes NO3- presence in the initial test sample,

⇒  [Fe(H2O)5]²⁺ + NO  →  Fe(H2O)5NO]²+ (brown ring)

8 0
2 years ago
Based on this equation: 2AL + 3CuCl2 -&gt; 2AlCl3 + Cu ... how many grams of copper(II) chloride dihydrate would be required to
PolarNik [594]
2Al + 3CuCl2 ➡ 2AlCl3 + 3Cu. Moles of Al = 1.2/27 = 0.045 moles 2 moles of Al reacts with 3 moles of CuCl2. Therefore, 1 mole of CuCl2 reacts with =2/3 x moles of Al = 2/3 x 0.045 = 0.03 moles.
6 0
3 years ago
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