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solong [7]
2 years ago
12

8xy^3*xy ^8 plsssssssssssssssssssss help

Mathematics
1 answer:
Sindrei [870]2 years ago
4 0

Answer:

x • (x^3 - 3x^2y + 3xy^2 + 7y^3)

Step-by-step explanation:

(8x • (y^3)) +  x • (x - y)^3

2^3xy^3 +  x • (x - y)^3

Evaluate :  (x-y)^3   =   x^3-3x^2y+3xy^2-y^3

Pull out like factors :

x^4 - 3x^3y + 3x^2y^2 + 7xy^3  =

x • (x^3 - 3x^2y + 3xy^2 + 7y^3)

x^3 - 3x^2y + 3xy^2 + 7y^3 is not a perfect cube

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3 years ago
Need help idk how to slove this
Gemiola [76]

Hi!

I'm not sure how to slove this, but I do know how to solve it ;D

<h3>We can't know the exact value of y, but we can isolate y on one side. First, multiply by z on both sides. </h3>

\frac{x+y}{z*z}=3*z

x + y = 3 * z

<h3>Now subtract x from both sides.</h3>

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<u>y = 3 * z - x</u>

<h2>The answer is y = 3 * z - x</h2>

Hope this helps! :)

-Peredhel

8 0
3 years ago
Read 2 more answers
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