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3 years ago

I need to find the volume Please show the procedure

Mathematics

2 answers:

joja [24]3 years ago

5 0

Volume of cuboid = l*b*h=5*6*7=210

[volume = area of base * height = (l*b)*h]

quester [9]3 years ago

3 0

The volume of a rectangular prism is the product of its three dimensions...

V=xyz in this case:

V=5*6*7=210 cm^3

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-4 3/5 divided by 1 1/5 as a mixed number or simplified

WITCHER [35]

-23 over 5 ÷ 11 over 5
-23 × 5 over 5 × 5
-115 over 55

Therefore, your answer would be: -2 and 1 over 11

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3 years ago

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Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

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2 years ago

One fabric cost $15.00 for 2 yards. Another cost $37.50 for 5 yards. Do both yards cost the same? Explain.

omeli [17]

Answer:

Yes.

Step-by-step explanation:

Both yards do cost the same.

$15.00 divided by 2 is equal to 7.5.

$37.50 divided by 5 is equal to 7.5.

Therefore, both yards cost the same.

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3 years ago

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Can someone please go over to my page and help me with this problem, its worth 99 points,no joke

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RoseWind [281]

Answer:

The answer to your question is Judaism, Christianity, Islam.

Step-by-step explanation:

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3 years ago

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