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I am Lyosha [343]

3 years ago

15

1. ¿Cuál de los factores se deben emplear para convertir: a. ¿Número de moles de cloro en número de moles de NaCl? b. Moles de s

odio a moles de cloro C. Moles de cloro a moles de sodio. 2 Na + CI, - 2 Naci
Ayudaaa

1 answer:

Alex3 years ago

7 0

Answer:

Número de moles de cloro en número de moles de NaCl

Explanation:

espero que si sea la correcta

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A gas has a density of 1.57 g/L at 40.0 Â°C and 2.00 atm of pressure. What is the identity of the gas?

Naddika [18.5K]

Answer:

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Explanation:

Step 1: Given and required data

Density of the gas (ρ): 1.57 g/L

Temperature (T): 40.0°C

Pressure (P): 2.00 atm

Ideal gas constant (R): 0.08206 atm.L/mol.K

Step 2: Convert T to Kelvin

We will use the following expression.

K = °C + 273.15 = 40.0 + 273.15 = 313.2 K

Step 3: Calculate the molar mass of the gas (M)

For an ideal gas, we will use the following expression.

ρ = P × M/R × T

M = ρ × R × T/P

M = 1.57 g/L × 0.08206 atm.L/mol.K × 313.2 K/2.00 atm

M = 20.17 g/mol

The gas with a molar mass of 20.17 g/mol is Neon.

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A student wants to make a 0.150 M aqueous solution of silver (I) nitrate but only has 11.27 g of AgNO3. What volume of the 0.150

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Answer:

442.3 mL

Explanation:

Remember that Molarity is a measure of concentration in Chemistry and it's defined as the number of moles of the substance divided by liters of the solution:

$M=\frac{Moles of substance X}{Volume of the solution}$

Then, you can express 11.27 g of AgNO3 as moles of AgNO3 using the molar mass of the compound:

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Then you can solve for the volume of the solution:

$Volume of the solution=\frac{Moles of AgNO_{3}}{M} =\frac{0.06634 mol AgNO_{3}}{0.150 M} =0.4423 L = 442.3 mL$

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