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vredina [299]
2 years ago
14

Hope you all have a great day ✝️ you are beautiful *muah* now go pick up your crown, here u go ** continue on love ya ​

Chemistry
1 answer:
Anni [7]2 years ago
3 0

Answer:Thank you, could you try to answer one of my questions I am in need of help.

Explanation:

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Which is the electron configuration for bromine?
murzikaleks [220]

Answer:

The first one

Explanation:

I can't read them well: it should be 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{5}

** this is the expanded version

3 0
3 years ago
What kind of waves do light waves travel in and how do they move
IgorLugansk [536]
Light is one form of energy that travels in electromagnetic waves. This energy is both magnetic and electrical. There are many different types of electromagnetic (EM) waves.
8 0
2 years ago
What are the advantages of using digital signals over analog signals?
Studentka2010 [4]

in digital signals, codes are used while in analogue signals do not use signals.

<h3>What are signals?</h3>

Signals are defined as the instructions which are transferred to another source in other to deliver a message.

There are two types of signals which include the digital and analogue signals.

The digital signals uses codes which is a secret way of sending messages while analogue doesn't use codes.

Learn more about codes here:

brainly.com/question/22654163

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4 0
2 years ago
A 1.0-L buffer solution is 0.10 M in HF and 0.050 M in NaF. Which action destroys the buffer? (a) adding 0.050 mol of HCl (b) ad
Volgvan

Answer:

(a) adding 0.050 mol of HCl

Explanation:

A buffer is defined as the mixture of a weak acid and its conjugate base -or vice versa-.

In the buffer:

1.0L × (0.10 mol / L) = 0.10 moles of HF -<em>Weak acid-</em>

1.0L × (0.050 mol / L) = 0.050 moles of NaF -<em>Conjugate base-</em>

-The weak acid reacts with bases as NaOH and the conjugate base reacts with acids as HCl-

Thus:

<em>(a) adding 0.050 mol of HCl:</em> The addition of 0.050moles of HCl produce the reaction of 0.050 moles of NaF producing HF. That means after the reaction, all NaF is consumed and you will have in solution just the weak acid <em>destroying the buffer</em>.

(b) adding 0.050 mol of NaOH: The NaOH reacts with HF producing more NaF. Would be consumed just 0.050 moles of HF -remaining 0.050 moles of HF-. Thus, the buffer <em>wouldn't be destroyed</em>.

(c) adding 0.050 mol of NaF: The addition of conjugate base <em>doesn't destroy the buffer</em>

3 0
3 years ago
I have no idea how to do this and need help
den301095 [7]

Answer:

60.55%

Explanation:

nO3=155/48

nO2 used: 3/2nO3=4.84375

percent yield: 4.84375/8=60.55%

5 0
3 years ago
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