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Brut [27]
3 years ago
8

A school janitor has mopped

Mathematics
2 answers:
Feliz [49]3 years ago
6 0
Answer:
The janitor is mopping 1 room every 15 minutes.

Explanation:
1/3 room = 5 minutes
1/3 x 3 = 3/3 and 5 x 3 = 15
He mops 1 room every 15 minutes.
Irina18 [472]3 years ago
3 0

Answer: 1 room every 15 minutes

Step-by-step explanation:

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How to change improper fraction to a mixed number​
Aleonysh [2.5K]

Answer:  

Step-by-step explanation :Answer

To chance an improper fraction into a mixed number first divide the numerator by the denominator

Example 11/5 divide 11 by 5 and you get 2.2 that means that 5 goes into 11 twice with some leftover which means the answer is going to be 2 plus a fraction

To get the fraction you multiply the denominator by the whole number you found (5*2) and subtract the numerator by that new number

5*2=10 11-10=1

Your new fraction is now 2 1/5

8 0
2 years ago
Read 2 more answers
Solve then graph each solution set on a number line <br><br> 2(w+36)+10&gt;32
goldenfox [79]
Ok the answer to your question is -25
5 0
3 years ago
The rate at which rain accumulates in a bucket is modeled by the function r given by r(t)=10t−t^2, where r(t) is measured in mil
mars1129 [50]

Answer:

36 milliliters of rain.

Step-by-step explanation:

The rate at which rain accumluated in a bucket is given by the function:

r(t)=10t-t^2

Where r(t) is measured in milliliters per minute.

We want to find the total accumulation of rain from <em>t</em> = 0 to <em>t</em> = 3.

We can use the Net Change Theorem. So, we will integrate function <em>r</em> from <em>t</em> = 0 to <em>t</em> = 3:

\displaystyle \int_0^3r(t)\, dt

Substitute:

=\displaystyle \int_0^3 10t-t^2\, dt

Integrate:

\displaystyle =5t^2-\frac{1}{3}t^3\Big|_0^3

Evaluate:

\displaystyle =(5(3)^2-\frac{1}{3}(3)^3)-(5(0)^2-\frac{1}{3}(0)^3)=36\text{ milliliters}

36 milliliters of rain accumulated in the bucket from time <em>t</em> = 0 to <em>t</em> = 3.

4 0
3 years ago
What is the surface area of the triangular prism?
Natalija [7]

Answer:

the answer is c

Step-by-step explanation:

7 0
3 years ago
HELP I NEED THIS NOW!!!!
borishaifa [10]

Answer:

<u>So, The area of trapezoid = 4.413 R²</u>

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and m∠NMK = 65° , OT = R

So, m∠MNP = 180° - 65° = 115° ⇒ supplementary interior angles.

<u>Join </u>ON ⇒ ΔOSN is a right triangle at S.

And NP, NM are tangents to the circle

So, ON bisects the angle ∠MNP = ∠MNS

∠ONS = (∠MNS)/2 = 115/2 = 57.5°

So, tan (∠ONS) = OS/NS = R/(NS)

NS = R/tan (∠ONS)=R/(tan 57.5°) ≈ 0.637 R

<u>∴ NP = 2 * NS = 1.274 R</u>

<u>Construct: a line parallel to ST from N to line MK</u>

let the intersection point be Q  ⇒ NQ = 2R

So, Δ NQM is a right triangle at Q

tan (∠NMQ) = tan 65 = NQ/MQ

MQ = NQ/(tan 65)=2R/tan 65 ≈ 0.932 R

∴ MK = 2 MT = 2 (MQ + QT) ⇒ QT = NS

         = 2 (MQ + NS ) = 2( 0.932 R + 0.637 R) = 2 * 1.569 R

<u>∴ MK = 3.139 R</u>

<u></u>

Now, area of trapezoid = height × (sum of parallel sides/ 2)

Area = ST * (NP + MK)/2

        = 2R * (1.274 R + 3.139 R) / 2

        = 2R * 4.413 R /2

       = 4.413 R²

So, The area of trapezoid = 4.413 R²

5 0
3 years ago
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