The coordinates of the image of Q in the sequence of transformations is Q' (1, -4)
<h3>How to determine the image of the transformation?</h3>
The complete question is added at the end of the solution
The coordinates of the triangle are given as
Q = (-2, 1)
R = (-4, 1)
S = (-4, 4)
The sequence of transformations is given as
- Translate the triangle 1 unit right and 5 units down.
- Reflect the triangle in the y-axis.
The rules of the above sequence of transformations are
- Translate the triangle 1 unit right and 5 units down: (x + 1, y - 5)
- Reflect the triangle in the y-axis: (-x, y)
When the above transformations are combined, we have
(x, y) = (-x - 1, y - 5)
So, we have
Q' = (2 - 1, 1 - 5) = (1, -4)
R' = (4 - 1, 1 - 5) = (3, -4)
S' = (4 - 1, 4 - 5) = (3, -1)
Hence, the image of the sequence of transformations is Q' (1, -4) and R' (3, -4) and S' (3, -1)
This means that the image of Q in the sequence of transformations is Q' (1, -4)
Read more about transformation at
brainly.com/question/27224272
#SPJ1
<u>Possible question</u>
If the coordinates of a triangle are Q (-2, 1), R (-4, 1) and S (-4, 4) and the transformation includes: translate the triangle 1 unit right and 5 units down. Then reflect the triangle in the y-axis.
Which figure is the image of Q?
