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Softa [21]
3 years ago
14

Dan took 12.5 seocnds to run the 100-meter dash during his track meet. He calculated the time to be approximently A) 0.283 minut

e B)750 minutes C) 0.2083 hour D)0.52083 hour
Mathematics
2 answers:
MrMuchimi3 years ago
6 0
60 second \div 60 = 1 minute\\\\12.5 seconds \div 60 = 0.208333... minute\\\\\\3600 seconds \div 3600 = 1 hour\\\\12.5 seconds \div 3600 = 0.00347222...hour
True [87]3 years ago
3 0
D would be the answer
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Consider a circle whose size can vary. Let r r represent the radius of the circle (in cm) and let C C represent the circumferenc
Ket [755]

Answer:

  f(r) = 2πr

Step-by-step explanation:

You know the formula for circumference in terms of radius is ...

  C = 2πr

You are being asked to write this as a function named "f". That will be ...

  f(r) = 2πr

8 0
3 years ago
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Pleaseee help me solve this
lapo4ka [179]

Answer:

f(x)=x² +3x-x/2

f(6)=(6)²+3(6)-6/2

= 36 + 18 -3

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3 years ago
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Jeremy used 11 gallons and 3 quarts of water to water his garden. How many quarts of water did Jeremy use?
Anon25 [30]

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6 0
2 years ago
Which is equivalent to log<br> 2 18 = x-1<br> 18^2 = x-1<br> 2^18 =x-1<br> 18^х-1=2<br> 2^x-1= 18
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Answer:

it the second one

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6 0
2 years ago
Given the relation y = 7x2 + 3, if the input is 4, what is the output? (4 points)
aivan3 [116]
I'm assuming that you meant: 
y = 7x² + 3 

Remember! Inputs are always x values (unless stated otherwise). Meaning the problem says: 
x = 4 

y = 7(4)² + 3 

The square only applies to the 4. The 7 is not going to be squared! (To be exact it only applies to whatever the value of x is. 

4² = 4·4 = 16

Remember: 
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Follow PEMDAS from left to right (or in the case above from top to bottom).

7·16 + 3 = ? 

16·7 = 10·7 + 6·7 = 70 + 42 = 112
(All I did to multiply was break it up into parts. If it confuses you don't worry about it, and just multiply it out like normal or use a calculator if you are allowed to)

112 + 3 = ? 

Our output is: 
115!
4 0
2 years ago
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