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Softa [21]
4 years ago
14

Dan took 12.5 seocnds to run the 100-meter dash during his track meet. He calculated the time to be approximently A) 0.283 minut

e B)750 minutes C) 0.2083 hour D)0.52083 hour
Mathematics
2 answers:
MrMuchimi4 years ago
6 0
60 second \div 60 = 1 minute\\\\12.5 seconds \div 60 = 0.208333... minute\\\\\\3600 seconds \div 3600 = 1 hour\\\\12.5 seconds \div 3600 = 0.00347222...hour
True [87]4 years ago
3 0
D would be the answer
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I’m having trouble with these types of questions.
german

The sum of all the angles in a triangle should always add up to 360° and seeing that this is an isosceles triangle 2 of the angles should be equal.

So there would be 2 30° angles and 360-60=300 so the 3rd angle would be equal to 300° . Hope this helps!

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3 years ago
Solve. T + 23 > 1 t > 24 t > –22 t < 24 t < –22
creativ13 [48]

t + 23 > 1     subtract 23 from both sides

t + 23 - 23 > 1 - 23

t > -22

5 0
3 years ago
Brian multiplied his average speed of 14.73 miles per hour by the amount of time he spent cross-country skiing. His product was
elixir [45]

Yes it was reasonable

Step-by-step explanation:

6 0
3 years ago
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Convert the Cartesian equation x^2 + y^2 = 16 to a polar equation.
Troyanec [42]

Answer:

2+2=4 16 divided by 4=4

Step-by-step explanation:

3 0
3 years ago
The Bay Area Online Institute (BAOI) has set a guideline of 60 hours for the time it should take to complete an independent stud
yarga [219]

Answer:

 At the 5% level, BAOI can infer that the average time to complete does not exceeds 60 hours.

Step-by-step explanation:

From the question we are told that

   The  population mean is \mu  =  60 \ hr

    The sample size is  n  =  16

    The  sample mean is  \= x  =  68 \ hr

     The  standard deviation is  \sigma  =  20 \ hr

The  null hypothesis is  H_o  :  \mu  =  60

The  alternative H_a :  \mu >  60

Here we would assume the level of significance of this test to be  

         \alpha  =  5\%  =  0.05

Next we will obtain the critical value of the level of significance from the normal distribution table, the value is    Z_{0.05} =  1.645

  Generally the test statistics  is mathematically represented as

           t =  \frac{ \= x  - \mu}{  \frac{ \sigma }{\sqrt{n} } }

substituting values

           t =  \frac{  68  - 60 }{  \frac{ 20 }{\sqrt{16} } }

          t = 1.6

Looking at the value of t and  Z_{\alpha } we see that t< Z_{\alpha } hence we fail to reject the null hypothesis

   This means that there no sufficient evidence to conclude that it takes more than 60 hours to complete the course

So

   At the 5% level, BAOI can infer that the average time to complete does not exceeds 60 hours.

6 0
3 years ago
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