I got 65 for my answer. Hope that helps!
Answer: The approximate area of the circle is: <span>3,629.84 cm² .</span>
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Area of a circle, "A" : A = π * r² ;
in which: A = Area of circle ;
π <span>≈ 3.14 ;
</span> r = radius;
radius of a circle, "r" = d / 2 ; in which: "d = diameter" ;
Given "d = 64 cm " ;
r = d / 2 = 64 cm / 2 = 32 cm ;
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So; A = π * r² ;
A ≈ (3.14) * (32 cm)² ;
A ≈ (3.14) * (1156 cm²) ;
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A ≈ 3,629 .84 cm² .
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Answer:
388.5yd²
Step-by-step explanation:
We have Triangle TUV
In the question, we are given already
Angle U = 32°
Angle T = 38°
Angle V = ???
Side t = 31yd
Side u = ?
Side v = ?
Area of the triangle= ?
Step 1
We find the third angle = Angle V
Sum of angles in a triangle = 180°
Third angle = Angle V = 180° - (32 + 38)°
= 180° - 70°
Angle V = 110°
Step 2
Find the sides u and v
We find these sides using the sine rule
Sine rule or Rule of Sines =
a/ sin A = b/ Sin B
Hence for triangle TUV
t/ sin T = u/ sin U = v/ sin V
We have the following values
Angle T = 38°
Angle U = 32°
Angle V = 110°
We are given side t = 31y
Finding side u
u/ sin U= t/ sin T
u/sin 32 = 31/sin 38
Cross Multiply
sin 32 × 31 = u × sin 38
u = sin 32 × 31/sin 38
u = 26.68268yd
u = 26.68yd
Finding side x
v / sin V= t/ sin T
v/ sin 110 = 31/sin 38
Cross Multiply
sin 110 × 31 = v × sin 38
v = sin 110 × 31/sin 38
v = 47.31573yd
v = 47.32yd
To find the area of triangle TUV
We use heron formula
= √s(s - t) (s - u) (s - v)
Where S = t + u + v/ 2
s = (31 + 26.68 + 47.32)/2
s = 52.5
Area of the triangle = √52.5× (52.5 - 31) × (52.5 - 26.68 ) × (52.5 - 47.32)
Area of the triangle = √150967.6032
Area of the triangle = 388.5454973359yd²
Approximately to the nearest tenth =388.5yd²
Answer:
a number
Step-by-step explanation:
this was asked in april so i rly think you need an answer anymore
Answer:
<em>64 degrees</em>
Step-by-step explanation:
When you have the SRQ angle, you can easily solve for PQR. Luckily, we're given that QRP and PRS are 32 and 84, respectively. Adding this together gives you 116. 116*2 = 232 and 360-232 = 128, and 128/2 = 64.
<em>Please Mark Brainliest if this helps!</em>
