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Yuri [45]
3 years ago
11

Cherry is booking a 3-night stay at a hotel. The rate is $45 per room plus tax.

Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

The lodging cost of the room is $ 41.28

Step-by-step explanation:

Given as :

The rate of room including taxes = $ 45

The state tax = 6 %

The city tax = 2 %

The municipal tax = 1 %

So, The total tax = 6 % + 2 % + 1 % = 9 %

Let The lodging cost  = $ x

So,  According to question

x + 9 % of x = $ 45

Or, x + 0.09 × x = 45

Or, 1.09 × x = 45

∴ x = \frac{45}{1.09} = $ 41.28

Hence The lodging cost of the room is $ 41.28   Answer

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A manager wishes to determine the relationship between the number of miles traveled​ (in hundreds of​ miles) by her sales repres
kati45 [8]

Answer:

y=3.53 x +37.92  

And for 0 miles if we use the model we got:

y(0)= 3.53*0 +37.92 = 37.92

But for this case. No is not reasonable for a representative to travel o miles and have a positive amount of sales.

Step-by-step explanation:

For this case we assume the following data:

Miles traveled (X): 2,3,10,7,8,15,3,1,11

Sales (Y): 31,33,78,62,65,61,48,55,120

We want to found a linear model like this one : y = mx+b. Where:

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=582-\frac{60^2}{9}=182  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=4329-\frac{60*553}{9}=642.33  

And the slope would be:  

m=\frac{642.33}{182}=3.529  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{60}{9}=6.667  

\bar y= \frac{\sum y_i}{n}=\frac{553}{9}=61.444  

And we can find the intercept using this:  

b=\bar y -m \bar x=61.444-(3.529*6.667)=37.917  

So the line would be given by:  

y=3.53 x +37.92  

And for 0 miles if we use the model we got:

y(0)= 3.53*0 +37.92 = 37.92

But for this case. No is not reasonable for a representative to travel o miles and have a positive amount of sales.

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3 years ago
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