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2 years ago

The ability to adjust to an artificially displaced or even inverted visual field is called

Physics

1 answer:

egoroff_w [7]2 years ago

3 0

Answer:

méthode if séparation muddy water

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Calculate the gravitational potential energy a 1kg ball has when thrown 3 m into the air. The gravitational field strength on ea

Andrei [34K]

Answer:

P.E.=29.4Nm

Explanation:

given data

m=1kg

h=3m

g=9.8m/s²

to find

gravitational potential energy=P.E.=?

solution

P.E.=mgh

PUTTING VALUES

P.E.=1kg×9.8m/s²×3m

P.E.=29.4Nm

3 0

3 years ago

Dimensional formula of Amplitude ?

jeka57 [31]

Answer:

The dimensional formula of the amplitude of a wave is given by,

[ M⁰L¹T⁰ ]

Where,

M = Mass

L = Length

T = Time

Derivation

The amplitude of wave = Maximum displacement

Since, the dimensional formula of displacement = [ M⁰L¹T⁰ ]

Therefore, the amplitude of a wave is dimensionally represented as [ M⁰L¹T⁰ ]

5 0

2 years ago

A leftward force of 7N is applied to a box while the force of friction is 3N. The weight of the box is 4N as is the normal force

Flauer [41]

Answer:

Explanation:

When you draw a free body diagram, You have a 7N arrow pointing left, and a 3N arrow pointing right. When you subtract the two, you still have a force of 4N on the left. However, seeing as how gravity is in play at a force of 4N, the two forces cancel out and you get 0N.

8 0

3 years ago

Ccording to coulomb's law, which pair of charged particles has the lowest potential energy? according to coulomb's law, which pa

Sladkaya [172]

Coulombs law says that the force between any two charges depends on the amount of charges and distance between them. This force is directly proportional to the magnitude of the two charges and inversely proportional to the distance between them.

$F=k\frac{|q_1| |q_2|}{r^2}$

where $q_1\hspace{1mm}and\hspace{1mm}q_2$ are charges, $r$ is the distance between them and k is the coulomb constant.

case 1:

$q_1=-e\\ q_2=+3e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||3e|}{(100pm)^2}=3ke^2\times10^8$

case 2

$q_1=-e\\ q_2=+2e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||2e|}{(100pm)^2}=2ke^2\times10^8$

case 3:

$q_1=-e\\ q_2=+e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||e|}{(200pm)^2}=0.25ke^2\times10^8$

Comparing the 3 cases:

The maximum potential force according to coulombs law is between -1 charge and +3 charge separated by a distance of 100 pm.

3 0

3 years ago

Read 2 more answers

PLEASE HELP!!!! Thank you!

V125BC [204]

it would be a chain reaction and a wave

6 0

3 years ago