There are approximately 39 inches in 6 meters.<span />
Answer:
Despite being such prominent feature on our planet, much of the mid-ocean ridge system remains a mystery. While we have mapped about half of the global mid-ocean ridge in high resolution, less than one percent of the mid-ocean ridge has been explored in detail using submersibles or remotely operated vehicles. so therefore we do not have enough information about them to know what will happen
Explanation:
A mid-ocean ridge or mid-oceanic ridge is an underwater mountain range, formed by plate tectonics. This uplifting of the ocean floor occurs when convection currents rise in the mantle beneath the oceanic crust and create magma where two tectonic plates meet at a divergent boundary. Mid-ocean ridges occur along divergent plate boundaries, where new ocean floor is created as the Earth’s tectonic plates spread apart. As the plates separate, molten rock rises to the seafloor, producing enormous volcanic eruptions of basalt. The speed of spreading affects the shape of a ridge slower spreading rates result in steep, irregular topography while faster spreading rates produce much wider profiles and more gentle slopes.
The true airspeed will increase and true altitude will increase.
<h3>
What is true air speed?</h3>
True airspeed is the airspeed of an aircraft relative to undisturbed air.
It's the aircraft speed relative to the airmass in which it's flying.
<h3>How does outside air temperature affect air speed?</h3>
If the outside air temperature increases during a flight at constant power and at a constant indicated altitude, the true airspeed will increase and true altitude will increase.
Thus, the true airspeed will increase and true altitude will increase.
Learn more about true airspeed here: brainly.com/question/13257916
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Answer:
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Explanation:
= Mass of the Earth = 5.98 × 10²⁴ kg
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
= Distance from the center of the Moon to the center of Earth = 6371000 m
= Distance from the center of the earth center to sun center
= Mass of moon = 
M = Mass of sun = 
Hence the force of moon on earth is 0.00566 times the force of earth on moon center to center
Answer: Magnitude of electric field = 6.77×10^11N/C
Explanation: Electric field= E =KQ/ r ^2
Given:
Total charge Q=53.2nc
Radius 84cm= 0.84m
Coulombs constant K= 8.987x10^9NmC^-1
E =(( 8.987×10^9) × 53.2) /(0.84^2)
E = ( 4 . 777 ×10 ^ 9 )/ 0.7056
E = 6.77 × 10^ 11 NC^-1
