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AveGali [126]
3 years ago
6

A car is traveling 80 km/h if the car's speed remains constant how far will it have traveled in 3 hours

Physics
1 answer:
12345 [234]3 years ago
7 0
C. 80 because it is remaining conctant
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Which ONE of the following pairs of physical quantities consists of one scalar and one vector quantity?
lyudmila [28]

Answer:

speed and acceleration

Explanation:

speed is a scalar quantity

acceleration is a vector quantity

7 0
2 years ago
What is the speed of a helicopter that traveled 1200 miles in 7 hours
zlopas [31]
1200
-------=171 miles per hour
7

8 0
3 years ago
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An object is observed for a time interval of 20 seconds. From time 6.7 s the object experiences a Force of 106 N that lasts unti
shusha [124]

Answer:

1654 kg m/s

Explanation:

The impulse experienced by an object is equal to the product between the force exerted on the object and the time during which the force lasts:

I=F\Delta t

where:

I is the impulse

F is the force exerted on the object

\Delta t is the time during which the force is applied

For the object in this problem, we have

F=106 N (force applied)

\Delta t= 15.6 s (time interval)

Therefore, the impulse experienced by the object is:

I=(106)(15.6)=1654 kg m/s

3 0
3 years ago
Calculate the frequency of the red light emitted by a neon sign with a wavelength of 690 nm
Ne4ueva [31]

Answer:

4.35 \times 10^{14} Hz

Explanation:

The frequency of a light is inversely proportional to its wavelength. It is given by:

f = \frac{v}{\lambda}

The speed of the red light, v = 3.0 × 10⁸ m/s

The wavelength of the red light, λ = 690 nm = 690 ×10⁻⁹ m

f = \frac{3.0 \times 10^8 m/s}{690\times 10^{-9}m} = 4.35 \times 10^{14} Hz

Thus, the frequency of red light emitted by neon sign having wavelength 690 nm is 4.35 \times 10^{14} Hz

7 0
3 years ago
Read 2 more answers
The steering wheel of a car has a radius of 0.19 m, and the steering wheel of a truck has a radius of 0.25 m. The same force is
kodGreya [7K]

Answer:

\frac{T_t}{T_c} = 1.32

Explanation:

The torque applied on an object can be calculated by the following formula:

T = Fr

where,

T = Torque

F = Applied Force

r = radius of the wheel

For car wheel:

T_c = Fr_c\\

For truck wheel:

T_t = Fr_t

Dividing both:

\frac{T_t}{T_c} = \frac{Fr_t}{Fr_c}

for the same force applied on both wheels:

\frac{T_t}{T_c} = \frac{r_t}{r_c} \\

where,

rt = radius of the truck steering wheel = 0.25 m

rc = radius of the car steering wheel = 0.19 m

Therefore,

\frac{T_t}{T_c} = \frac{0.25\ m}{0.19\ m} \\

\frac{T_t}{T_c} = 1.32

8 0
3 years ago
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