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lapo4ka [179]
3 years ago
9

A point charge q = -0.45 nC is fixed at the origin. Where must an electron be placed in order for the electric force acting on i

t to be exactly opposite to its weight? (Let the y axis be vertical with the positive direction pointing up.)
Physics
1 answer:
ziro4ka [17]3 years ago
3 0

Answer:

Electron must be placed at a distance of 2.69 ×10^5 m in the direction of positive y-axis.

Explanation:

Charge on electron = e = -1.6 × 10^-19 C

Mass of electron = m = 9.1 × 10^-31 kg

Charge at origin = q = -0.45 nC  

According to given condition in the question:

                       Fe = Fg

                   kq1q2/r^2 = mg  

(9 × 10^9)( -1.6 × 10^-19)( -0.45n)/r^2 = (9.1 × 10^-31)(9.8)

                    r = √7.2 ×10^10

                    r = 2.69 ×10^5 m      in the positive y-axis direction  

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A pressure sensor inside of a mixing tank is designed to turn red when the pressure inside the tank exceeds 1.9 kPa. If the sens
spin [16.1K]

Answer:

19 N

Explanation:

From the question given above, the following data were obtained:

Pressure (P) = 1.9 kPa

Length (L) = 10 cm

Force (F) =?

Next, we shall convert 1.9 KPa to N/m². This can be obtained as follow:

1 KPa = 1000 N/m²

Therefore,

1.9 KPa = 1.9 KPa × 1000 N/m² / 1 KPa

1.9 KPa = 1900 N/m²

Thus, 1.9 KPa is equivalent to 1900 N/m².

Next, we shall convert 10 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

10 cm = 10 cm × 1 m / 100 cm

10 cm = 0.1 m

Thus, 10 cm is equivalent to 0.1 m

Next, we shall determine the area of the square. This can be obtained as follow:

Length (L) = 0.1 m

Area of square (A) =?

A = L²

A = 0.1²

A = 0.01 m²

Thus, the area of the square is 0.01 m².

Finally, we shall determine the force that must be exerted on the sensor in order for it to turn red. This can be obtained as follow:

Pressure (P) = 1900 N/m²

Area (A) = 0.01 m²

Force (F) =?

P = F/A

1900 = F / 0.01

Cross multiply

F = 1900 × 0.01

F = 19 N

Therefore, a force of 19 N must be exerted on the sensor in order for it to turn red.

3 0
3 years ago
Given: G = 6.672 × 10−11 N · m2 /kg2 Io, a satellite of Jupiter, has an orbital period of 1.24 days and an orbital radius of 4.1
Dahasolnce [82]

Answer:

Mass of Jupiter = 4.173×10^15kg

Explanation:

Using Kepler's 3rd law, it states that the orbital period T is related to the distance,r as:

T^2 = GM/4 pi × r^3

Where G = universal gravitational constant

r = radius

M = masd of jupiter

Rearranging the formular to make M the subject of formular

T^2 × 4 pi = G M × r^3

(T^2 × 4 pi) / (G× r^3) = M

(1.24^2 × 4 × 3.142) /(6.672×10^-11)(4.11×10^8)^3

M = 19.32 /6.672×10^-11)(4.11×10^8)^3

M = 19.32 / 4.63 ×10^15

M = 4.173×10^15kg

6 0
3 years ago
If you use a force of 90 N to pick up a 10 pound bag of charcoal, what is the acceleration?
hjlf

Answer:

9ms^2

Explanation:

since ,Force=mass*acceleration

then, acceleration=force/mass

and, Force=90N

Mass=10pound

therefore, acceleration=90/10

=9ms^2

8 0
3 years ago
The temperature of water in a beaker is 45°C. What does this measurement represent
andrezito [222]
Based on my information, this would actually be representing "the average kinetic energy of water particles". So, as you take notice that where this temperature is being located, and also, how this would be 45°C, this would make more sense for this to be representing as <span>the average kinetic energy of water particles.</span>
3 0
3 years ago
Read 2 more answers
(a) What is the fluid speed in a fire hose with a 9.00-cm diameter carrying 80.0 L of water per second? (b) What is the flow rat
son4ous [18]

Answer:

12.5752053801 m/s

80\times 10^{-3}\ m^3/s

No.

Explanation:

Q = Volume flow rate = 80\ L/s=80\times 10^{-3}\ m^3/s

d = Diameter of pipe = 9 cm

A = Area = \dfrac{\pi}{4}d^2

Volume flow rate is given by

Q=Av\\\Rightarrow v=\dfrac{Q}{A}\\\Rightarrow v=\dfrac{80\times 10^{-3}}{\dfrac{\pi}{4} (9\times 10^{-2})^2}\\\Rightarrow v=12.5752053801\ m/s

Velocity of fluid is 12.5752053801 m/s

The volume flow rate in m³/s is 80\times 10^{-3}\ m^3/s

The flow of fluid does not depend on the type of water used. Hence the answers would be same. If Q is constant v will be the same irrespective of the type of water used.

8 0
3 years ago
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