Answer:
See explaination
Explanation:
1) Pb(NO3)2 => Pb2+ + 2 NO3-
[Pb2+] = [Pb(NO3)2] = 7.56 mM = 7.56 x 10-3 M
Pb(IO3)2 <=> Pb2+ + 2 IO3-
Ksp = [Pb2+][IO3-]2 = 2.5 x 10-13
7.56 x 10-3 x [IO3-]2 = 2.5 x 10-13
[IO3-] = 5.75 x 10-6 M ≈ 5.8 x 10-6 M
(2) [Pb2+] = 1.7 x 10-6 M
Ksp = [Pb2+][IO3-]2 = 2.5 x 10-13
1.7 x 10-6 x [IO3-]2 = 2.5 x 10-13
[IO3-] = 3.83 x 10-4 M
[IO3-]from Pb(IO3)2 = 2 x [Pb2+]
= 2 x 1.7 x 10-6 = 3.4 x 10-6 M
[IO3-]from NaIO3 = [IO3-] - [IO3-]from Pb(IO3)2
= 3.83 x 10-4 - 3.4 x 10-6
= 3.80 x 10-4 M
NaIO3 => Na+ + IO3-
[NaIO3] = [IO3-]from NaIO3
= 3.80 x 10-4 M ≈ 3.8 x 10-4 M
