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Tema [17]
3 years ago
15

Calculate the volume of hydrogen needed to saturate the double bonds in 100 g of linoleic acid (RMM = 280).

Chemistry
1 answer:
klasskru [66]3 years ago
4 0

Answer:

                     15.99 dm³

Explanation:

The molecular formula of Linoleic acid is C₁₈H₃₂O₂. As shown in attached figure, the Linoleic acid contains two double bonds hence we can say that in the Hydrogenation reaction of Linoleic acid 2 mole of H₂ are added across the two double bonds to make it saturated (Stearic acid).

The balance chemical equation for the hydrogenation of Linoleic acid is as follow:

                            C₁₈H₃₂O₂ + 2 H₂  →  C₁₈H₃₆O₂

Calculating moles of Linoleic acid:

                    Moles = Mass / M/Mass

                    Moles = 100 g / 280 g/mol

                    Moles = 0.357 moles Linoleic acid

Calculating moles of Hydrogen:

According to equation:

1 mole C₁₈H₃₂O₂ required  =  2 moles of H₂

So,

0.357 moles Linoleic acid will require  =  X moles of H₂

Solving for X,

                        X  =  2 moles × 0.357 moles / 1 mole

                        X  =  0.714 moles of H₂

Calculating volume of Hydrogen Gas:

Let us assume that the volume is calculated at standart temperature (273.15 K) and pressure (1 atm). We know that STP,

                         1 mole of gas occupies  =  22.4 dm³ of volume

So,

              0.714 moles of gas will occupy  = X dm³ of volume

Solving for X,

                     X =  22.4 dm³ × 0.714 moles / 1 mole

                     X =  15.99 dm³

Note: As the answer is not 17.28 dm³ so it means that the conditions for gas like temperature and pressure are different and are not mentioned in statement. Hence, if the conditions are known then one can use ideal gas equation i.e. PV=nRT to solve for volume.

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Answer:

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Explanation:

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We can balance it using the ion-electron method.

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Step 2: Perform the mass balance, adding H⁺(aq) and H₂O(l) where appropriate

MnO₄⁻(aq) + 8 H⁺(aq) → Mn²⁺(aq) + 4 H₂O(l)

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Step 3: Perform the charge balance, adding electrons where appropriate

MnO₄⁻(aq) + 8 H⁺(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l)

2 I⁻(aq) → I₂(s)  + 2 e⁻

Step 4: Multiply both half-reactions by numbers so that the number of electrons gained and lost are equal

2 × (MnO₄⁻(aq) + 8 H⁺(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l))

5 × (2 I⁻(aq) → I₂(s)  + 2 e⁻)

Step 5: Add both half-reactions and cancel what is repeated on both sides

2 MnO₄⁻(aq) + 16 H⁺(aq) + 10 e⁻ + 10 I⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 I₂(s)  + 10 e⁻

The balanced reaction is:

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Explanation:

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The beta particle released is basically a electron with -1 charge and no mass.

General representation of beta particle in the form of _Z^A\textrm {X} given as _{-1}^0e

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8 0
3 years ago
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dsp73

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 0.037 M

<u>Explanation:</u>

We are given:

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<u>At eqllm:</u>        1.0-2x          x           x

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Neglecting the negative value of 'x' because concentration cannot be negative

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