Step-by-step explanation:
the y values are still the same size as for the regular f(x).
so, answers c and d are out.
it is just that these same y values are happening in a more squeezed interval as for the regular f(x).
when we look at the endpoints for example, we find that
y = f(x) delivers y = -2 for x = 4
but the red function delivers y = -2 already for x = 2.
similar for y = 2, originally for x = 2, but in red for x = 1.
and for y = -1, originality for x = -2, but in red for x = -1.
let's call the original function black, and the new function red.
so, in other words red(2) = black(4)
red(1) = black(2)
red(-1) = black(-2)
=>
red(x) = black(2x)
and therefore, a. is correct
