Most likely, the equation is
<em>Acceleration over a period of time = </em>
<em>(change in speed during the period of time)</em>
<em>divided by</em>
<em>(length of the period of time) .</em>
for any piece of the graph.
The velocity of light is v = 3 x 10⁸ m/s.
The given wavelength is λ = 0.86 nm = 0.86 x 10⁻⁹ m.
Note that
v = fλ
where f = frequency.
Therefore
f = (3 x 10⁸ m/s)/(0.86 x 10⁻⁹ m)
= 3.488 x 10¹⁴ Hz
Answer: 3.49 x 10¹⁴ Hz
Answer:
6logs
Explanation:f
First finding the volume of the logs
V= π/4d²l
= 0.098m³
So number of logs will be
Weight of 2 boys + weight of log = buoyancy force.
So
2( 400)+ N ( Mlog x g) = density of water x volume displaced x g
2(400) = N x 0.098x 1000x 9.8 x 0.9- 0.75* 1000
N= 5.5 which is approx 6logs
Answer:
The new pressure is 4 times of the initial pressure.
Explanation:
Given that,
The pressure of an ideal gas is 4 atm.
We need to find the change in the pressure of the gas if the temperature by a factor of 4.
We know that,
PV = nKT ....(1)
P = pressure, V = volume, T = temperature
Let P' is the new pressure of the gas. So,
P'V= nK(4T) ......(2)
Dividing equation (1) and (2) we get :
It means that the new pressure is 4 times of the initial pressure.