Given : f(x)= 3|x-2| -5
f(x) is translated 3 units down and 4 units to the left
If any function is translated down then we subtract the units at the end
If any function is translated left then we add the units with x inside the absolute sign
f(x)= 3|x-2| -5
f(x) is translated 3 units down
subtract 3 at the end, so f(x) becomes
f(x)= 3|x-2| -5 -3
f(x) is translated 4 units to the left
Add 4 with x inside the absolute sign, f(x) becomes
f(x)= 3|x-2 + 4| -5 -3
We simplify it and replace f(x) by g(x)
g(x) = 3|x + 2| - 8
a= 3, h = -2 , k = -8
Answer:
Step-by-step explanation:
Answer:
Just divide the numbers by 10 and then multiply the quotient by 2. hope this helped
Answer:
The circle's centre is at the position (3, 5), and it has a radius of 2
Step-by-step explanation:
First let's put it in a useful format by completing the squares:
x² + y² - 6x - 10y + 30 = 0
x² - 6x + y² - 10y = -30
x² - 6x + 9 + y² - 10y + 25 = -30 + 9 + 25
(x - 3)² + (y - 5)² = 4
This tells us that the centre position is (3, 5) and the radius is √4, or 2
Answer:
the answer to the problem is 35.
