Answer:
i have this question too. im not sure but i think its maximum
Step-by-step explanation:
Answer:
Today: Tuesday, 12th January 2021
21.16 PM
![\tt 5x - 9 > 12](https://tex.z-dn.net/?f=%20%5Ctt%205x%20-%209%20%3E%2012)
![\tt 5x > 12 + 9](https://tex.z-dn.net/?f=%20%5Ctt%205x%20%3E%2012%20%2B%209)
![\tt 5x > 21](https://tex.z-dn.net/?f=%20%5Ctt%205x%20%3E%2021)
![{\orange{\boxed{ \red{\tt x = \frac{21}{5} }}}}](https://tex.z-dn.net/?f=%20%20%7B%5Corange%7B%5Cboxed%7B%20%5Cred%7B%5Ctt%20x%20%20%3D%20%20%5Cfrac%7B21%7D%7B5%7D%20%7D%7D%7D%7D)
When you know one factor and the product, divide the product by the known factor to get the missing factor.
56/7=8
Final answer: 8
Answer:
The value of the limit is 12.
Step-by-step explanation:
Small typing mistake, the limit is of h tending to 0.
We have that:
![f(x) = x^{3}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%5E%7B3%7D)
Then
![f(2+h) = (2+h)^{3} = 8 + 12h + 6h^{2} + h^{3}](https://tex.z-dn.net/?f=f%282%2Bh%29%20%3D%20%282%2Bh%29%5E%7B3%7D%20%3D%208%20%2B%2012h%20%2B%206h%5E%7B2%7D%20%2B%20h%5E%7B3%7D)
![f(2) = 2^{3} = 8](https://tex.z-dn.net/?f=f%282%29%20%3D%202%5E%7B3%7D%20%3D%208)
Calling the limit L
![L = \frac{f(2+h) - f(2)}{h}](https://tex.z-dn.net/?f=L%20%3D%20%5Cfrac%7Bf%282%2Bh%29%20-%20f%282%29%7D%7Bh%7D)
![L = \frac{8 + 12h + 6h^{2} + h^{3} - 8}{h}](https://tex.z-dn.net/?f=L%20%3D%20%5Cfrac%7B8%20%2B%2012h%20%2B%206h%5E%7B2%7D%20%2B%20h%5E%7B3%7D%20-%208%7D%7Bh%7D)
![L = \frac{h^{3} + 6h^{2} + 12h}{h}](https://tex.z-dn.net/?f=L%20%3D%20%5Cfrac%7Bh%5E%7B3%7D%20%2B%206h%5E%7B2%7D%20%2B%2012h%7D%7Bh%7D)
h is the common term in the numerator, then
![L = \frac{h(h^{2} + 6h + 12)}{h}](https://tex.z-dn.net/?f=L%20%3D%20%5Cfrac%7Bh%28h%5E%7B2%7D%20%2B%206h%20%2B%2012%29%7D%7Bh%7D)
Simplifying by h
![L = h^{2} + 6h + 12](https://tex.z-dn.net/?f=L%20%3D%20h%5E%7B2%7D%20%2B%206h%20%2B%2012)
Since h tends to 0.
![L = 0^{2} + 6*0 + 12](https://tex.z-dn.net/?f=L%20%3D%200%5E%7B2%7D%20%2B%206%2A0%20%2B%2012)
![L = 12](https://tex.z-dn.net/?f=L%20%3D%2012)
So the answer is 12.