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3 years ago

Decide whether the given number is a solution of the given equation.

Mathematics

2 answers:

Yakvenalex [24]3 years ago

5 0

Answer:

Step-by-step explanation:

-7+12=5

Ymorist [56]3 years ago

3 0

Answer:

$x=7$

-7 is not a solution for $x+12=19$

Step-by-step explanation:

$x +12 = 19$

Subtract 12 from both sides

$x = 19-12$

Subtract 12 from 19 to get 7

$x = 7$

It would be -7 if it was $-x+12=19$

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Which number is irrational?<br> 16.5%<br> 0.0675<br> 8 3/4<br> 3.14

eimsori [14]

Answer:

3.14

Step-by-step explanation:

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4 years ago

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iogann1982 [59]

34.76

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Explanation:

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18) =

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3 years ago

Simplify each answer into a fraction, Please show work as well!

scoray [572]

Answer: 1) 8/15 2) 2 4/9 3) -13/45

Step-by-step explanation:

1/5 + 1/3 = 6/30 + 10/30 = 16/30 = 8/15

2 1/9 + 1/3 = 19/9 + 3/9 = 22/9 = 2 4/9

1/9 - 2/5 = 5/45 - 18/45 = -13/45

7 0

3 years ago

What is f(g(x)) for x > 5?

mel-nik [20]

Answer:

$\large\boxed{B.\ 4x^2-41x+105}$

Step-by-step explanation:

$f(x)=4x-\sqrt{x}\\\\g(x)=(x-5)^2\\\\f(g(x))\to\text{put}\ x=(x-5)^2\ \text{to}\ f(x):\\\\f(g(x))=f\bigg((x-5)^2\bigg)=4(x-5)^2-\sqrt{(x-5)^2}\\\\\text{use}\\(a-b)^2=a^2-2ab+b^2\\\sqrt{x^2}=|x|\\\\f(g(x)=4(x^2-2(x)(5)+5^2)-|x-5|\\\\x>5,\ \text{therefore}\ x-5>0\to|x-5|=x-5\\\\f(g(x))=4(x^2-10x+25)-(x-5)\\\\\text{use the distributive property:}\ a(b+c)=ab+ac\\\\f(g(x))=(4)(x^2)+(4)(-10x)+(4)(25)-x-(-5)\\\\f(g(x))=4x^2-40x+100-x+5\\\\\text{combine like terms}\\\\f(g(x))=4x^2+(-40x-x)+(100+5)\\\\f(g(x))=4x^2-41x+105$

6 0

3 years ago

Read 2 more answers

What would be the expression after distributing, -3(x+5)?

polet [3.4K]

Answer:

-3x-15

Step-by-step explanation:

-3*x

-3*5

7 0

3 years ago

Read 2 more answers