Please don't ask 2 questions in 1 question
remember that percent is parts out of 100 so x%=x/100
basically just remove the percent sign and move the decimal place 2 places to the left to convert to fraction
the first one
20 dollars
4.75% tax
15% tip
it depends if you want to tip on the total with tax or without tax
it is better to top on the without-tax value since tax comes from you so
find 4.75% of 20 and add that to 15% of 20 then add that to 20 to get the proper value
scenarios
1. 20+(20 times 4.75%)+(20 times 15%)=23.95
2. ([(20 times 104.75%)] times 115%)=24.09
both are bellow $25 so $25 shoudl be enough to cover it
total cost of a spa treatment of 42 with 6% tax and 20% tip
so you could again do two things:
1. apply tax and give tip on the new amount
2. find the tip and add that to the tax of only 42
scenarios:
1.(42 times 106%) times 120%=$50.4
2. (42 times 20%) +(42 times 106%)=$52.92
it depens on what you tip on
Answer:
this is a function
Step-by-step explanation:
the x does not repeat itself
Answer:
51
Step-by-step explanation:
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
</span>
The answer to the problem is c
