A readymade cube or a cube that you can make with paper and wood sticks?
Translations move the pre-image horizontally or vertically, but retain its orientation.
Reflections reflect across axes, mirroring the pre-image. Reflections result in a change of orientation.
Dilations stretch or shrink the pre-image by a scale factor; they change the pre-image's size but retain the pre-image's orientation.
Rotations rotate around a center point, but don't change the direction of the shape (its orientation).
Answer:
g. reflections
Dividing 3,724 by 6 would equal 620.66666666 repeating. Or 620.667
Hope this helped :)
Answer:
3n + 7 < 16
Step-by-step explanation:
7 more than 3 times a number, n, is less than 16 is represented by
3n + 7 < 16 where:
3n = three times a number, n,
+ 7 = 7 more than
and
< 16 = is less than 16.
The values of s in the interval [0, 2π) such that tan s = -(√3)/3 are 5π/6 and 11π/6.
What is trigonometry and how is it assessed?
Simply put, trigonometric functions—also referred to as circular functions: are the functions of a triangle's angle. This means that these trig functions provide the relationship between the angles and sides of a triangle. Sine, cosine, tangent, cotangent, secant, and cosecant are the fundamental trigonometric functions. Numerous trigonometric identities and formulas indicate the relationship between the functions and aid in determining the triangle's angles.
The quadrants determine the values of the trigonometric functions.
Given, tan s = -(√3)/3 ⇒ tan s = -(√3)/(√3)² ⇒ tan s = (-1)/(√3)
Therefore, the simplified value of tangent of s is tan s = (-1)/(√3)
Again the interval of the function is [0, 2π), so only the second and fourth quadrants can contain the given value of tangent being negative.
For the value of s in second quadrant, we have:
tan s = (-1)/(√3) ⇒ tan s = tan (π - (π/6)) ⇒ tan s = tan (5π/6) ⇒ s = 5π/6
For the value of s in the fourth quadrant, we have:
tan s = (-1)/(√3) ⇒ tan s = tan (2π - (π/6)) ⇒ tan s = tan (11π/6) ⇒ s = 11π/6
Thus, the values of s in the interval [0, 2π) such that tan s = -(√3)/3 are 5π/6 and 11π/6.
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