HELP TIMED BRAINLY POINTS

Write the contrapositive and the converse of the following conditional

Lunna [17]

The contrapositive statement are:

If the lake is frozen, then it isn't cold.
If Solomon is happy, then he isn't healthy.
If Tigist does not take a walk, then it will not rain

<h3>What is the converse statement?</h3>

The converse statement are:

If the late is frozen, then it is cold.
If Solomon is happy, then he is healthy.
If Tigist Tigist does not take a walk, then it will rain.

Note that the converse of a statement is created by the act of switching the hypothesis given and also the conclusion.

Therefore, The contrapositive statement are

If the lake is frozen, then it isn't cold.
If Solomon is happy, then he isn't healthy.
If Tigist does not take a walk, then it will not rain

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6 0

1 year ago

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(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

Explanation:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

Step(i):-

Given differential problem

y′+3 y=9 t

Take the Laplace transform of both sides of the differential equation

L( y′+3 y) = L(9 t)

Using Formula Transform of derivatives

L(y¹(t)) = s y⁻(s)-y(0)

By using Laplace transform formula

$L(t) = \frac{1}{S^{2} }$

Step(ii):-

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

Step(iii):-

By using partial fractions , we get

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

B = 9/3 = 3

Put s = -3 in equation(i)

9 = C(-3)²

C = 1

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

0 = A + C

put C=1 , becomes A = -1

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

Step(iv):-

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

By using inverse Laplace transform

$L^{-1} (\frac{1}{s} ) =1$

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

Final answer:-

Now the solution , we get

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

2 years ago

HELP PLEASE I NEED HELP QUICKLY!!!

agasfer [191]

It would be the 2nd answer....your initial value (read from the left of the line graph) is 4.....following the line to the first even point you can see it has dropped 3 for the 4 points it has moved to the right....giving -3/4 as the rate of change.

3 0

2 years ago

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How do you find the area of a triangle?

kirza4 [7]

Hello!

We use formulas to find the areas of different shapes. The formula for the area of a triangle is:

1/2 bh

These means that you must multiply the base by the height and then divide it by two.

Good Day!

4 0

2 years ago

How do I get the answer 2100 divided by 33

Reptile [31]

Answer: 700/11

Step-by-step explanation:

Because....

when you divide 2100 by 33 you get a decimal like, 63.6363636364. Therefor, you turn the decimals into a fraction. So the decimals become 700/11.

* Hopefully this helps:) Mark me the brainliest:)!!

5 0

3 years ago

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