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3 years ago

A taxi

Physics

1 answer:

nignag [31]3 years ago

3 0

That taxi will traveled 1500s by carrying the passenger.

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A man is dragging a trunk up the loading ramp of a mover’s truck. The ramp has a slope angle of 20.0°, and the man pulls upward

AleksandrR [38]

Answer:

(a) 104 N

(b) 52 N

Explanation:

Given Data

Angle of inclination of the ramp: 20°

F makes an angle of 30° with the ramp

The component of F parallel to the ramp is Fx = 90 N.

The component of F perpendicular to the ramp is Fy.

(a)

Let the +x-direction be up the incline and the +y-direction by the perpendicular to the surface of the incline.

Resolve F into its x-component from Pythagorean theorem:

Fx=Fcos30°

Solve for F:

F= Fx/cos30°

Substitute for Fx from given data:

Fx=90 N/cos30°

=104 N

(b) Resolve r into its y-component from Pythagorean theorem:

Fy = Fsin 30°

Substitute for F from part (a):

Fy = (104 N) (sin 30°)

= 52 N

5 0

3 years ago

Need help with formula: H(t) = -16^2 + vt + s

Rom4ik [11]

<span> The equation is h(t) = at^2 + vt + d where a = acceleration of gravity = - 32.174 ft/sec^2 v = 25 feet/sec d = starting height = 0 and h(t) = 0 when the ball hits the ground. So, 0 = - 32.174t^2 + 25t + 0 You can use the quadratic formula on that if you want, or you can solve like this: 0 = - 32.174t^2 + 25t 0 = t ( -32.174t + 25) So, one solution of that is t = 0, corresponding to the initial time when the ball is kicked. The other time is: 25 = 32.174t t = 25/32.174 = 0.777 seconds or approximately 0.8 seconds.</span>

4 0

4 years ago

A neutron in a nuclear reactor makes an elastic head-on collision with the nucleus of a plutonium atom initially at rest. (a) Wh

olga55 [171]

Answer:

Fraction = 59049/60025

Explanation:

Let m be the mass of the neutron and M be the mass of the plutonium nucleus (at rest)

Now, formula for kinetic energy before collision is;

K_i = ½mu²

Formula for kinetic energy after collision is;

K_f = ½mv²

Where;

u is the velocity of the neutron before collision

v is the velocity of the neutron after collision.

From collision principle where momentum before collision equals momentum after collision, we can say that;

(m - M)u = (m + M)v

Thus,

v = [(m - M)u]/(m + M)

Putting [(m - M)u]/(m + M) for v in the final kinetic energy equation gives;

K_f = ½m([(m - M)u]/(m + M))²

K_f = ½mu²((m - M)²/(m + M)²)

To get the fraction of the neutron's kinetic energy is transferred to the plutonium nucleus, it is simply;

K_f/K_i = [½mu²((m - M)²/(m + M)²)]/½mu²

This gives;

K_f/K_i = ((m - M)²/(m + M)²)

But mass of plutonium = 244m

Thus;

K_f/K_i = ((m - 244m)²/(m + 244m)²)

K_f/K_i = 59049m²/60025m²

K_f/K_i = 59049/60025

4 0

3 years ago

5. Confirm dimensionally that the product (lvp/n) is

Sidana [21]

Answer:

How do you do it?

Explanation:

7 0

3 years ago

Weight is measured in units called

Aleksandr-060686 [28]

Pounds

If you are talking about the unit of measurement for weight is that of force it would be Newtons.

8 0

3 years ago