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crimeas [40]
3 years ago
8

A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a sp

eed of 60.0m/s. Air resistance may be ignored,so the water balloon is in free fall after it leaves the throwers hand. a) What is its speed after falling for 2.00s? b) How far does it fall in 2.00s? c) What is the magnitude of its velocity after falling 10.0m?
Physics
1 answer:
Aliun [14]3 years ago
5 0

Answer: velocity = 79.6m/s, distance covered = 139.6m and velocity when distance is 10.0m = 61.611m/s

Explanation:

First step is to take a direction of motion, so to avoid issues with negative sign, I take my direction of motion as the positive y axis which makes the parameters positive.

The object is of a free fall thus it has a constant acceleration of g = 9.8m/s².

a) initial velocity (u) = 60m/s, g = 9.8m/s², time taken (t) =2s, we need to get velocity at that time using the formulae below

v = u + at

v = 60 + (9.8)* 2

v = 60 + 19.6

v = 79.6m/s

b) to get the distance traveled at t =2s, we use the formulae below

s =ut + 1/2at² where s = distance covered.

s = 60 * 2 + 1/2 * 9.8 * 2²

s = 120 + 1/2 *9.8 * 4

s = 120 + 9.8 * 2

s = 120 + 19.6

s = 139.6m

c) to get the velocity (v) when distance traveled (s) = 10m, we use the formulae below.

v² = u² + 2as

v² = 60² + 2( 9.8)(10)

v² = 3600 + 196

v² = 3796

v = √3796

v = 61.611m

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valkas [14]

Answer: m∠P ≈ 46,42°

because using the law of sines in ΔPQR

=> sin 75°/ 4 = sin P/3

so ur friend is wrong due to confusion between edges

+) we have: sin 75°/4 = sin P/3

=> sin P = sin 75°/4 . 3 = (3√6 + 3√2)/16

=> m∠P ≈ 46,42°

Explanation:

4 0
3 years ago
A shuttle on Earth has a mass of 4.5 E 5 kg. Compare its weight on Earth to its weight while in orbit at a height of 6.3 E 5 met
faltersainse [42]

Answer:

83%

Explanation:

On the surface, the weight is:

W = GMm / R²

where G is the gravitational constant, M is the mass of the Earth, m is the mass of the shuttle, and R is the radius of the Earth.

In orbit, the weight is:

w = GMm / (R+h)²

where h is the height of the shuttle above the surface of the Earth.

The ratio is:

w/W = R² / (R+h)²

w/W = (R / (R+h))²

Given that R = 6.4×10⁶ m and h = 6.3×10⁵ m:

w/W = (6.4×10⁶ / 7.03×10⁶)²

w/W = 0.83

The shuttle in orbit retains 83% of its weight on Earth.

4 0
3 years ago
If you run at 8m/s for 15 minutes how far will you go
sashaice [31]

Answer: 7200 m

Explanation: The solution is, first convert 15 minutes to seconds.

15 mins x 60 s / 1 min = 900 s

Use the formula for speed which is v= d/t then derive for d.

d = vt

= 8 m/s ( 900s)

= 7200 m

6 0
3 years ago
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The Earths magnetic field deflects the flow of current from?
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<span>Most of the earth's fresh water is stored as ice in the Arctic and Antarctic regions of the globe.</span>
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3 years ago
Two blocks of masses M 1 and M 2 are connected by a massless string that passes over a massless pulley as shown in the figure. M
stealth61 [152]

The mass M1 is 7.8 kg

Explanation:

Block M1 is hanging on the string while block M2 is on the frictionless ramp.

We have to write the equations of motion for the two blocks.

- For M1, the only two forces acting on it are the force of gravity M_1 g (downward) and the tension in the string T (upward). So we can write

M_1 g - T = M_1 a

where

M_1 is the mass of the block

g=9.8 m/s^2 is the acceleration of gravity

a is the acceleration of the system

- For M2, the only two forces acting on it are the tension in the string T (acting up along the ramp) and the component of the gravity acting down along the ramp, M_2 g sin \theta. So the equation of motion is

T-M_2 g sin \theta = M_2 a

where

M_2 = 13.5 kg is the mass of the 2nd block

\theta=35.5^{\circ} is the angle of the ramp

In order for the two blocks to be in equilibrium, the acceleration must be zero:

a=0

So the two equations become:

M_1 g - T=0\\T-M_2 g sin \theta = 0

Isolating T from the 1st equation,

T=M_1 g

And substituting into the 2nd equation, we can find the value of the mass M_1:

M_1 g - M_2 g sin \theta = 0\\M_1 = M_2 sin \theta = (13.5)(sin 35.5^{\circ})=7.8 kg

Learn more about acceleration and forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

7 0
3 years ago
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