Answer: velocity = 79.6m/s, distance covered = 139.6m and velocity when distance is 10.0m = 61.611m/s
Explanation:
First step is to take a direction of motion, so to avoid issues with negative sign, I take my direction of motion as the positive y axis which makes the parameters positive.
The object is of a free fall thus it has a constant acceleration of g = 9.8m/s².
a) initial velocity (u) = 60m/s, g = 9.8m/s², time taken (t) =2s, we need to get velocity at that time using the formulae below
v = u + at
v = 60 + (9.8)* 2
v = 60 + 19.6
v = 79.6m/s
b) to get the distance traveled at t =2s, we use the formulae below
s =ut + 1/2at² where s = distance covered.
s = 60 * 2 + 1/2 * 9.8 * 2²
s = 120 + 1/2 *9.8 * 4
s = 120 + 9.8 * 2
s = 120 + 19.6
s = 139.6m
c) to get the velocity (v) when distance traveled (s) = 10m, we use the formulae below.
v² = u² + 2as
v² = 60² + 2( 9.8)(10)
v² = 3600 + 196
v² = 3796
v = √3796
v = 61.611m
