What has more thermal energy a small balloon or a large balloon

Physics

2 answers:

Firlakuza [10]3 years ago

7 0

Answer:

large balloon

Explanation:

Thermal energy is the amount of energy contained in a system solely by the effect of its temperature. However, this concept should not be confused with that of internal energy. Internal energy, in turn, is defined as the sum of kinetic energy (translational, rotational and vibrational) with the different forms of potential energy (attractive or repulsive) that can exist between the molecules of a body.

Kinetic energy is associated with the movement of molecules, while potential energy is energy that can be stored in a physical system. In the case of balloons filled with air or liquids, the larger the balloon, the greater the kinetic potential and consequently the thermal energy. For example, a large balloon filled with air will have more thermal energy, because it will have more air molecules that will move through the kinetic energy causing thermal energy.

mrs_skeptik [129]3 years ago

5 0

The average kinetic energy of these individual particles causes an effect we can sense—warmth. ... The air in the air-filled balloon absorbed thermal energy from the flame and started moving faster. The increased movement of the molecules of air expanded the balloon and plastic of the balloon quickly melted. So the big one

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An underwater scuba diver sees the Sun at an apparent angle of 43.0° above the horizontal. What is the actual elevation angle of

Inessa05 [86]

Answer:

The actual elevation angle is 12.87 degrees

Explanation:

In the attachment you can clearly see the situation. The angle of elevation as seen for the scuba diver is shown in magenta, we conclude that $\theta_2=90-43=47$ .

Using Snell's Law we can write:

$n_1\sin(\theta_1)=n_2\sin(\theta_2)$

$\implies \sin(\theta_1)=\frac{n_2}{n_1}\sin(\theta_2)$ ,

Let's approximate the index of refraction of the air (medium 1 in the picture) to 1.

We thus have:

$\sin(\theta_1)=n_2\sin(\theta_2)=1.333\sin(47)$

$\implies\theta_1=\arcsin[n_2\sin(\theta_2)]=\arcsin[1.333\sin(47)]\approx 77.13$ . Calling $\alpha$ the actual angle of elevation, we get from the picture that $\alpha=90-77.13=12.97$