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3 years ago

What has more thermal energy a small balloon or a large balloon

Physics

2 answers:

Firlakuza [10]3 years ago

7 0

Answer:

large balloon

Explanation:

Thermal energy is the amount of energy contained in a system solely by the effect of its temperature. However, this concept should not be confused with that of internal energy. Internal energy, in turn, is defined as the sum of kinetic energy (translational, rotational and vibrational) with the different forms of potential energy (attractive or repulsive) that can exist between the molecules of a body.

Kinetic energy is associated with the movement of molecules, while potential energy is energy that can be stored in a physical system. In the case of balloons filled with air or liquids, the larger the balloon, the greater the kinetic potential and consequently the thermal energy. For example, a large balloon filled with air will have more thermal energy, because it will have more air molecules that will move through the kinetic energy causing thermal energy.

mrs_skeptik [129]3 years ago

5 0

The average kinetic energy of these individual particles causes an effect we can sense—warmth. ... The air in the air-filled balloon absorbed thermal energy from the flame and started moving faster. The increased movement of the molecules of air expanded the balloon and plastic of the balloon quickly melted. So the big one

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A red laser beam goes from crown glass with refraction index n=1.3 to air (n=1) with an incident angle of 0.23 radians. What is

Klio2033 [76]

Answer:

θ = 10.28º

Explanation:

To find the angle of refraction use the equation of refraction

n₁ sin θ₁ = n₂ sin θ₂

where index 1 is for incident light and index 2 is for refracted light.

sin θ₂ = n₁ / n₂ sin θ

let's calculate

sin = 1 / 1.3 sin 0.23

sin = 0.175

θ= 0.17528 rad

let's reduce to degrees

θ = 0.17528 rad (180ª / pi rad)

θ = 10.28º

6 0

3 years ago

A player kicks a football from ground level with a velocity of 26.2m/s at an angle of 34.2° above the horizontal. How far back f

Amanda [17]

For the ball to go straight into the goal, the kicker needs to be no more than 6.54 meters away from the goal.

For the ball to arc into the goal, the kicker needs to be between 58.5 and 65.1 meters away from the goal.

<h3>Explanation</h3>

How long does it take for the ball to reach the goal?

Let the distance between the kicker and the goal be $x$ meters.

Horizontal velocity of the ball will always be $26.2\times\cos{34.2\textdegree}$ until it lands if there's no air resistance.

The ball will arrive at the goal in $\displaystyle \frac{x}{26.2\times\cos{34.2\textdegree}}$ seconds after it leaves the kicker.

What will be the height of the ball when it reaches the goal?

Consider the equation

$\displaystyle h(t) = -\frac{1}{2}\cdot g\cdot t^{2} + v_{0,\;\text{vertical}} \cdot t + h_0$ .

For this soccer ball:

$g = 9.81\;\text{m}\cdot\text{s}^{-2}$ ,
$v_{0,\;\text{vertical}} = 26.2\times \sin{34.2\textdegree{}}\;\text{m}\cdot\text{s}^{-2}$ ,
$h_0 = 0$ since the player kicks the ball "from ground level."

$\displaystyle t=\frac{x}{26.2\times\cos{34.2\textdegree}}$

when the ball reaches the goal.

$\displaystyle h= - 9.81 \times \frac{x^2}{(26.2\times\cos{34.2\textdegree})^2} + (26.2 \times \sin{34.2\textdegree})\times\frac{x}{26.2\times\cos{34.2\textdegree}} \\\phantom{h} = -\frac{9.81}{(26.2\times\cos{34.2\textdegree})^2}\cdot x^{2} + \frac{\sin{34.2\textdegree}}{\cos{34.2\textdegree}}\cdot x$ .

Solve this quadratic equation for $x$ , $x > 0$ .

$x = 65.1$ meters when $h = 0$ meters.
$x = 6.54$ or $58.5$ meters when $h = 4$ meters.

In other words,

For the ball to go straight into the goal, the kicker needs to be no more than 6.54 meters away from the goal.
For the ball to arc into the goal, the kicker needs to be between 58.5 and 65.1 meters away from the goal.