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Nikitich [7]
2 years ago
14

Please help me ASAP...​

Mathematics
1 answer:
jolli1 [7]2 years ago
6 0

Answer:

<em>a</em><em>)</em><em>x</em><em>=</em><em> </em><em>68</em><em>°</em>

<em>b</em><em>)</em><em>x</em><em>=</em><em> </em><em>40</em><em>°</em>

<em>c</em><em>)</em><em>y</em><em>=</em><em> </em><em>115</em><em>°</em><em> </em><em>x</em><em>=</em><em> </em><em>65</em><em>°</em>

<em>d</em><em>)</em><em>y</em><em>=</em><em> </em><em>57</em><em>°</em><em> </em><em>x</em><em>=</em><em> </em><em>59</em><em>°</em>

<em>e</em><em>)</em><em>x</em><em>=</em><em> </em><em>47</em><em>°</em><em> </em><em>y</em><em>=</em><em> </em><em>43</em><em>°</em><em> </em><em>z</em><em>=</em><em> </em><em>133</em><em>°</em>

<em>f</em><em>)</em><em>x</em><em>=</em><em> </em><em>71</em><em>°</em>

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Each person in a group of college students was identified by graduating year and asked when he or she preferred taking classes:
swat32

Answer:

<em>0.615</em>

Step-by-step explanation:

The frequency table is attached below.

We have to calculate, the probability that the student preferred morning classes given he or she is a junior.

i.e P(\text{Morning }|\text{ Junior})

We know that,

P(A\ |\ B)=\dfrac{P(A\ \cap\ B)}{P(B)}

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Read 2 more answers
The largest z-score available in most tables is 2.99, which corresponds to a probability of 99.86%. A fair coin is
lana66690 [7]

Answer:

The number of heads observed is 121.14 heads

Step-by-step explanation:

The formula for the z-score of a proportion is given as follows;

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{pq}{n}}}

Where:

{\hat{p} = Sample proportion

p = Population success proportion = 0.5

q = 1 - p = 1 - 0.5 = 0.5

n = Number in of observation = 200

z = 2.99

Hence, we have;

z=\dfrac{\hat{p}-0.5}{\sqrt{\dfrac{0.5 \times 0.5}{200}}} = 2.99

Therefore;

{\hat{p}-0.5}{} = 2.99 \times \sqrt{\dfrac{0.5 \times 0.5}{200}} = 2.99 \times\dfrac{\sqrt{2} }{40}

{\hat{p} = 0.6057

Whereby \ \hat p = \dfrac{Number \ of \ heads}{Number \ of \ observation} =  \dfrac{Number \ of \ heads}{200} = 0.6057

∴ The number of heads observed = 200 × 0.6057 = 121.14 heads.

5 0
3 years ago
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