The empirical formula : C₂Cl₇
The molecular formula : C₁₀Cl₃₅
<h3>Further explanation</h3>
Given
8.81 g Carbon
91.2 g Chlorine
Molar Mass: 1362.5 g/mol
Required
The empirical formula and molecular formula
Solution
Mol ratio :
C = 8.81 g : 12.011 g/mol =0.733
Cl = 91.2 g : 35,453 g/mol = 2..572
Divide by 0.733
C : Cl = 1 : 3.5 = 2 : 7
The empirical formula : C₂Cl₇
(The empirical formula)n = the molecular formula
(C₂Cl₇)n = 1362.5
(2x12.011+7x35.453)n=1362.5
(272.193)n=1362.5
n = 5
The simple trick which one can consider in such problem where it is asked for positron emission is :
<span>When the atomic number goes DOWN by one and mass number remains unchanged, then a positron is emitted.
</span>
<span>a. </span>

<span>
Here the atomic number decreases by one.
Similarly, options b and d are eliminated.
Option c is also not the answer.
For c, Count the atomic number on left side and compare it with right side. You will see it is 9 on left and 8 on right. Atomic no. did go down by 1. But the atomic mass is changed as well.
</span>
Answer:c
Explanation:because the light is hitting the Earth straight on without a slant or without all the light, it is the most direct
Answer:
1.53x10^22 atoms of Au
Explanation:
To find the atoms of gold we need first, to convert the mass of gold to moles using molar mass of gold (196.97g/mol). Then, these moles must be converted to number of atoms based on definition of moles (1 mole = 6.022x10²³ atoms).
<em>Moles Au:</em>
5.00g Au * (1mol / 196.97g) = 0.0254 moles of Au
<em>Atoms of Au:</em>
0.0254 moles * (6.022x10²³ atoms / 1 mole) =
<h3>1.53x10^22 atoms of Au</h3>